Round 287.9412 to the nearest tenth. Do not write extra zeros.
2 answers:
Hello Friend!
287.9412...
Well now, what we need to remember is that when rounding up we can only do that if the number is 5 or above 5.
We also need to know what place is the tenths place....
287.9412
^ there you have it!
Now if we look at the number before it.... it's a 4 but that is less than 5 so we need to round it down... our answer would be 100%:
287.9
Therefore, that is The Correct Answer^^^ 287.9.
I Hope my answer has come to your Help. Thank you for posting your question here in
We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)
287.9412...
Well now, what we need to remember is that when rounding up we can only do that if the number is 5 or above 5.
We also need to know what place is the tenths place....
287.9412
^ there you have it!
Now if we look at the number before it.... it's a 4 but that is less than 5 so we need to round it down... our answer would be 100%:
287.9
Therefore, that is The Correct Answer^^^ 287.9.
I Hope my answer has come to your Help. Thank you for posting your question here in
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Answer:
And when we apply the limit we got that:
Step-by-step explanation:
Assuming this complete problem: "The following formula for the sum of the cubes of the first n integers is proved in Appendix E. Use it to evaluate the limit . 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2"
We have the following formula in order to find the sum of cubes:
We can express this formula like this:
And using this property we need to proof that: 1^3+2^3+3^3+...+n^3=[n(n+1)/2]^2
If we operate and we take out the 1/4 as a factor we got this:
We can cancel and we got
We can reorder the terms like this:
We can do some algebra and we got:
We can solve the square and we got:
And when we apply the limit we got that: