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Radda [10]
2 years ago
6

Round 287.9412 to the nearest tenth. Do not write extra zeros.

Mathematics
2 answers:
vazorg [7]2 years ago
4 0
Hello Friend!

287.9412...
 
Well now, what we need to remember is that when rounding up we can only do that if the number is 5 or above 5.  

We also need to know what place is the tenths place....
287.9412
        ^ there you have it!

Now if we look at the number before it.... it's a 4 but that is less than 5 so we need to round it down... our answer would be 100%:

287.9

Therefore, that is The Correct Answer^^^ 287.9.

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

(Ps. Mark As Brainliest IF Helped!)

-TheOneAboveAll :D
goldenfox [79]2 years ago
3 0
Salutations!

<span>Round 287.9412 to the nearest tenth. 

Lets solve this!

To round to the nearest tenth, you need to know the tenth place--------

In the number, 287.9412, nine is in the tenth place. You need also make sure whether the number next to 9 is greater than 5 or not. 

</span><span>287.9412 =287.941=287.94=287.9=288=290

Thus, your answer is 290.

Hope I helped.
</span>
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What is 2 (log Subscript 3 Baseline 8 + log Subscript 3 Baseline z) minus log Subscript 3 Baseline (3 Superscript 4 Baseline min
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Answer:

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Step-by-step explanation:

Given expression is,

2\left(\log_3\left(8\right)+\log_3\left(z\right)\right)-\log_3\left(3^4-7^2\right)

Now using logarithmic rule to solve the expression as follows,

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Therefore,

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Applying power rule of logarithmic,

a\log_c\left(b\right)=\log_c\left(b^a\right)

Therefore,

\log_3\left(\left(8z\right)^2\right)-\log_3\left(3^4-7^2\right)

\log_3\left(\left(64z^2\right)\right)-\log_3\left(3^4-7^2\right)

Applying quotient rule of logarithmic,

\log_c\left(a\right)-\log_c\left(b\right)=\log_c\left(\frac{a}{b}\right)

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Simplifying,

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