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Likurg_2 [28]
2 years ago
9

Betsy works as waitress. Today she worked an 8 hour shift, and was paid $ 92.00. Plot a graph of the amount Betsy earns against

the time she works for. Then find how much Betsy is paid per hour. Write an equation using Y = MX + B Form.
Mathematics
2 answers:
Allushta [10]2 years ago
6 0

Answer:

it would be 93 if you follow the rules of math

Katyanochek1 [597]2 years ago
5 0

your answer should be 93

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Jed entered the following values into the TVM Solver on his graphing calculator.
Elden [556K]

Answer: 17.7

Step-by-step explanation:

69/ 3.9%•100= 17.69= 17.7

8 0
2 years ago
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ali's typing rate between 8:00 am and noon is 48 words per minute . after lunch a lunch break, Ali's typing rate between 1:00 pm
gavmur [86]

Answer:

41 word/min

Step-by-step explanation:

Before noon Ali works:

  • 4 hours= 4*60 min= 240 min

She types:

  • 240*48= 11520 words

After lunch she works:

  • 4 hours

She types:

  • 4*2040= 8160 words

Total Ali works= 4+4= 8 hours= 480 min

Total Ali types= 11520+8160= 19680 words

Average typing rate= 19680 words/480 min= 41 word/min

3 0
2 years ago
A stereo manufacturer makes three types of stereo systems, I, II, and III, with profits of $20, $30, and $40, respectively. No m
romanna [79]
So,

1. Type I profits $20
2. Type II profits $30
3. Type III profits $40
4. I/day < 100
5. Type I needs 5 hrs.
6. Type II needs 10 hrs.
7. Type III needs 15 hrs.
8. Total hrs. available: 2000 hrs.

Every +5 hrs. spent yields an extra $10.
If we use 500 hrs. to make 100 Type I stereos, we will profit $2000.
If we use 500 hrs. to make 50 Type II stereos, we will profit $1500.
If we use 495 hrs. to make 33 Type III stereos, we will profit $1320.

We should use the first 500 hrs. to make Type I stereos.
We should use the last 1500 hrs. to make Type II stereos.

$2000 + $4500 = x
$6500 = x

There must be 100 Type I stereos made along with 150 Type II stereos made.
4 0
2 years ago
Which values are within the range of the piecewise-defined function? f(x) = StartLayout enlarged left-brace 1st Row 1st column 2
Otrada [13]

Answer:

the answer is below frum ed

Step-by-step explanation:

y= -6

Y= -4

Y= -3

Y= 0

8 0
2 years ago
Read 2 more answers
A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot
Damm [24]

Answer:

a) p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) \hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.  

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

\hat p represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

z_{\alpha/2} represent the critical value for the margin of error

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

\hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545

0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.  

5 0
2 years ago
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