So to solve this you would make a tree with the first soup choices branching off into the other choices. Then when you wrote down all the possibilitys you would count all them and get your answer or you could just do 2*4*2=16
<span> so there would be 16 possibilitys </span>
The sum of arithmetic series is given by:
Sn=n/2(a1+an)
where:
n=number of terms
a1=first term
an=nth term
but
n=18, an=275, Sn=4185
plugging the values in the formula we get:
4185=18/2(a1+275)
simplifying this we get:
4185=9(a1+275)
dividing through by 9 we get:
465=a1+275
thus
a1=465-275
a1=190
Answer: first number is 190
A random supporter roots the home team with probability 0.9, and the away team with probability 0.1.
Choosing 6 out of 8 supporters who root for the home team has probability
Answer:
1/2 (1 half)
Step-by-step explanation:
The number of different sandwiches is calculated multiplying all of the possibilities for each material used:
rye or white bread: 2 options
ham or turkey: 2 options
cheese or no cheese: 2 options
So the number of different sandwiches that can be made is 2*2*2 = 8.
From these 8 different sandwiches, 4 have cheese and 4 have no cheese, as the staff made a equal number of each type of sandwich.
So, if from 8 different type of sandwiches, 4 have cheese, the chances of Mary getting a sandwich with cheese is 4/8 = 1/2 (1 half).
Let's call Tacos t and Enchiladas e.
Lily paid $9 for 2t and 3e
Alex paid $12.50 for 3t and 4e.
Thus the equations would be.
