Answer:
<u>0.9524</u>
Step-by-step explanation:
<em>Note enough information is given in this problem. I will do a similar problem like this. The problem is:</em>
<em>The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?</em>
<em />
<u>Solution:</u>
This is conditional probability.
Given:
- Probability train arrive on time and leave on time = 0.8
-
Probability train arrive on time = 0.84
-
Probability train leave on time = 0.86
Now, according to conditional probability formula, we can write:
= P(arrive ∩ leave) / P(arrive)
Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"
and
P(arrive) means probability arriving on time given as 0.84, so:
0.8/0.84 = <u>0.9524</u>
<u></u>
<u>This is the answer.</u>
Given:
<span>12-foot wire is secured from the ground to the tree at a point 10 feet off the ground.
The tree meets the ground at a right angle.
When you visualize the scenario, the 12 foot wire would be the measure of the hypotenuse and the 10 feet off the ground will be the short leg or opposite. The long leg or adjacent is unknown.
We need to solve for sine theta because the value of hypotenuse and opposite is given.
sin </span>θ = opposite / hypotenuse
sin θ = 10 feet / 12 feet
sin θ = 0.833
θ = 0.83 / sin
θ = 56°
The wire would meet the ground at approximately 56° angle.
Correct question is ;
The grade appeal process at a university requires that a jury be structured by selecting eight individuals randomly from a pool of nine students and eleven faculty. (a) What is the probability of selecting a jury of all students? (b) What is the probability of selecting a jury of all faculty? (c) What is the probability of selecting a jury of six students and two faculty?
Answer:
A) 7.144 × 10^(-5)
B) 0.00131
C) 0.0367
Step-by-step explanation:
We are given;
Number of students = 9
Number of faculty members = 11
A) Now, the number of ways we can select eight students from 9 =
C(9, 8) = 9!/(8! × 1!) = 9
Also, number of ways of selecting 8 individuals out of the total of 20 = C(20,8) = 20!/(8! × 12!) = 125970
Thus, probability of selecting a jury of all students = 9/125970 = 7.144 × 10^(-5)
B) P(selecting a jury of all faculty) = (number of ways to choose 8 faculty out of 11 faculty)/(Total number of ways to choose 8 individuals out of 20 individuals) = [C(11,8)]/[C(20,8)] = (11!/(8! × 3!))/125970 = 0.00131
C) P(selecting a jury of six students and two faculty) = ((number of ways to choose 6 students out of 9 students) × (number of ways to choose 2 faculty out of 11 faculty))/(Total number of ways to choose 8 individuals out of 20 individuals) = [(C(9,6) × C(11,2)]/125970
This gives;
(84 × 55)/125970 = 0.0367
Answer:
1 - If method I is used, population of generalization will include all those people who may have varying exercising habits or routines. They may or may not have a regular excersing habit. In his case sample is taken from a more diverse population
2 - Population of generalization will include people who will have similar excersing routines and habits if method II is used since sample is choosen from a specific population
Step-by-step explanation:
Past excercising habits may affect the change in intensity to a targeted excersise in different manner. So in method I a greater diversity is included and result of excersing with or without a trainer will account for greater number of variables than method II.
Answer:
Step-by-step explanation:
Using the area model and standard algorithm, we have:
332 (tenths)
<u> × 21 </u>
332
<u> 664 </u>
<u> 6972 </u> tenths = 697.2
<u />
30 + 3 tenths
1 300 32 332
20 600 64 664
33.2 × 21 =<u> 30 </u> × <u> 1 </u> = <u> 30 </u>
