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PSYCHO15rus [73]
2 years ago
13

Darlene spent 20 minutes jogging and 10 minutes cycling and burned 400 calories . The next day she did 10 minutes of jogging and

20 minutes of cycling and burned 350 calories . How many calories were burned for each minute of jogging and how many for each minute of cycling

Mathematics
2 answers:
Anton [14]2 years ago
7 0

This is very spread out just to show properly but you could get it smaller haha

Sphinxa [80]2 years ago
6 0

Answer:

Jogging=15

Cycling= 10

Step-by-step explanation:

20j+10c=400

20j=40c=700

30c=-300

300/30=10

j=10

10j+20(10)350

10j+200=350

10j=350-200

10j=150

150/10=15

j=15

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Answer:

a) p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) \hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

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Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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Part a

Description in words of the parameter p

p represent the real population proportion of people who showed partial or complete resistance to the antibiotic

\hat p represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

z_{\alpha/2} represent the critical value for the margin of error

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p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

\hat p=\frac{973}{1714}=0.568 represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

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0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545

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