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pentagon [3]
2 years ago
14

The average weight of 6 packages is (9m + 8) pounds. 2 more packages, with weights of (12m + 12) pounds and (14m + 12) pounds, a

re added to the original 6 packages. Find the average weight of the 8 packages
Mathematics
1 answer:
Rainbow [258]2 years ago
7 0
6 packages+17m pounds
2 more packages =50m pounds

17m+50m=----m
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Which equation is the inverse of (x minus 4) squared minus two-thirds = 6y minus 12?
mario62 [17]

Answer:

The correct option is option B.

Step-by-step explanation:

The given function is

(x - 4)^{2} - \frac{2}{3} = 6y - 12

We can rearrange the function as

(x - 4)^{2} - \frac{2}{3} = 6y - 12

⇒ 3(x - 4)² - 2 = 18y - 36

⇒ 3(x - 4)² = 18y - 34

⇒ (x - 4)^{2} = 6y - \frac{34}{3}

⇒ x - 4 = \pm \sqrt{6y - \frac{34}{3}}

⇒ x = 4 \pm \sqrt{6y - \frac{34}{3}}

Therefore, the inverse function will be, y = 4 \pm \sqrt{6x - \frac{34}{3}}

Therefore, the correct option is option B. (Answer)

7 0
2 years ago
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Mustafa, Heloise, and Gia have written more than a combined total of 2222 22 articles for the school newspaper. Heloise has writ
Papessa [141]

Answer: m>8

Mustafa could have written more than 8 articles for the newspaper.

Step-by-step explanation:

Given: Heloise has written 1/4 as many articles as Mustafa has. Gia has written 3/2 as many articles as Mustafa has.

Let m be the number of articles Mustafa writes.

Then articles written by Heloise=\frac{1}{4}m

And articles written by Gia=\frac{3}{2}m

The total number of articles =m+\frac{1}{4}m+\frac{3}{2}m=\frac{4m+m+6m}{4}=\frac{11m}{4}

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

\frac{11m}{4}>22\\\Rightarrow\ m>\frac{22\times4}{11}\\\Rightarrow\ m>8

Hence, Mustafa could have written more than 8 articles for the newspaper.

3 0
2 years ago
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Factor 125x9 + 64. (5x3 – 4)(25x6 + 20x3 + 16) (5x3 – 4)(25x3 + 20x3 + 16) (5x3 + 4)(25x6 – 20x3 + 16) (5x3 + 4)(25x3 – 20x3 + 1
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(5x^3 + 4)(25x^6 - 20x3 +16)  remember factoring the cubes?
4 0
2 years ago
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A bridge is rated to a capacity of 100 British tons. What is the maximum weight the bridge can support in kilograms? (Round to t
S_A_V [24]

Maximum weight the bridge can support in kilograms is 101696

Step-by-step explanation:

  • Step 1: Given capacity of bridge = 100 British tons. Find how many kilograms are equivalent to 1 British ton.

1 British ton = 2240 pounds

1 pound = 0.454 kg

⇒ 1 British ton = 2240 × 0.454 kg = 1016.96 kg

  • Step 2: Find how many kilograms are in 100 British tons.

⇒ 100 × 1016.96 = 101696

3 0
2 years ago
Graph f(x)=−0.5x+3. Use the line tool and select two points to graph the line.
NikAS [45]

Answer: These are some points of the grahp:

(-2,4)

(0, 3)

(2, 2)


Explanation:


1) f(x) =  -0.5x + 3, is the equation of the form y = mx + b


2) y = mx + b is slope-intercept  equation of a line where the slope is m and the y-intercept is b, so, f(x) = - 0.5x + b has slope m = -0.5 and y-intercept b = 3.


3) To graph f(x) = -0.5x + 3, follow these steps:

  • draw two perpedicular axis: vertical axis, labeled y, and horizontal axis, labeled x.
  • draw marks on each axis, each mark equivalent to one unit.
  • the intersection point of the vertical and horizontal axis is the origin, i.e. point (0,0).
  • you can make a table with two or more points:

        x       f(x) = - 0.5x + 3

        -2         4

        0          3

        2          2

        4           1

        6          0


4) You can see the graph in the figure attached, and select any of the points on the line either by using the table or by using the equation f(x) = -0.5x + 3.

8 0
2 years ago
Read 2 more answers
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