0.08(y + -1) + 0.12y = 0.14 + -0.05(10)
Reorder the terms:
0.08(-1 + y) + 0.12y = 0.14 + -0.05(10)
(-1 * 0.08 + y * 0.08) + 0.12y = 0.14 + -0.05(10)
(-0.08 + 0.08y) + 0.12y = 0.14 + -0.05(10)
Combine like terms: 0.08y + 0.12y = 0.2y
-0.08 + 0.2y = 0.14 + -0.05(10)
Multiply -0.05 * 10
-0.08 + 0.2y = 0.14 + -0.5
Combine like terms: 0.14 + -0.5 = -0.36
-0.08 + 0.2y = -0.36
Solving
-0.08 + 0.2y = -0.36
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '0.08' to each side of the equation.
-0.08 + 0.08 + 0.2y = -0.36 + 0.08
Combine like terms: -0.08 + 0.08 = 0.00
0.00 + 0.2y = -0.36 + 0.08
0.2y = -0.36 + 0.08
Combine like terms: -0.36 + 0.08 = -0.28
0.2y = -0.28
Divide each side by '0.2'.
y = -1.4
Simplifying
y = -1.4
Answer:
The independent would be the 15 tickets and the dependent would be the t-shirt
Step-by-step explanation:
ABCD is a parallelogram Given
AE=CE, BE=DE <span>The diagonals of a parallelogram are bisect each other
</span>∠AEB=∠CED Vertical angles are congruent
ΔABE is congruent to ΔCDE SAS theorem<span>
</span>
Answer:
1131 pounds.
Step-by-step explanation:
We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.
First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:
The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.
Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.
Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.
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