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1 year ago

Find the perimeter of △CDE. Round your answer to the nearest hundredth. The perimeter is about units.

Mathematics

1 answer:

Troyanec [42]1 year ago

8 0

Answer: $9.66\ units$

Step-by-step explanation:

The triangle CDE is shown in the image attached.

The formula for calculate the distance between two points is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Then, we can calculate the lenght of each side of the triangle:

$d_{CD}=\sqrt{(4-4)^2+(-5-(-1))^2}=4\ units\\\\d_{DE}=\sqrt{(4-2)^2+(-5-(-3))^2}=2.828\ units\\\\d_{CE}=\sqrt{(2-4)^2+(-3-(-1))^2}=2.828\ units$

Therefore, the perimeter is:

$P=4\ units+ 2.828\ units+2.828\ units=9.66\ units$

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The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − (x − π/2) + 1/6 (x − π/2)3 + R3(x). Usin

Otrada [13]

Answer:

The cosine of 86º is approximately 0.06976.

Step-by-step explanation:

The third degree Taylor polynomial for the cosine function centered at $a = \frac{\pi}{2}$ is:

$\cos x \approx -\left(x-\frac{\pi}{2} \right)+\frac{1}{6}\cdot \left(x-\frac{\pi}{2} \right)^{3}$

The value of 86º in radians is:

$86^{\circ} = \frac{86^{\circ}}{180^{\circ}}\times \pi$

$86^{\circ} = \frac{43}{90}\pi\,rad$

Then, the cosine of 86º is:

$\cos 86^{\circ} \approx -\left(\frac{43}{90}\pi-\frac{\pi}{2}\right)+\frac{1}{6}\cdot \left(\frac{43}{90}\pi-\frac{\pi}{2}\right)^{3}$

$\cos 86^{\circ} \approx 0.06976$

The cosine of 86º is approximately 0.06976.

8 0

2 years ago

Ella’s test grades in her history class are 89, 94, 82, 84, and 98. What score must Ella make on her next test to have a mean te

aksik [14]

Mean is same as average

to find average
add up terms
divided that sum by the number of terms you have
example

mean of x,y,z
x+y+z
3 terms
(x+y+z)/3=mean

so
represent next test score as x
89+94+82+84+98+x
count how many terms ther are (6 terms)

mean is 90
(89+94+82+84+98+x)/6=90
add the like terms
(447+x)/6=90
multiply both sides by 6 to clear fraction
447+x=540
subtract 447 from both sides
x=93

she needs a score of 93 on next test

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earnstyle [38]

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Hi there!

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If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)

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