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MatroZZZ [7]
1 year ago
8

Frank's Auto Corner recorded its sales for the second quarter (April, May and June) of 1999. April sales were 89 cars, May sales

were 98 cars, and June sales were 115 cars. During the same quarter in the previous year, 1998, the total sales were 287 cars. How many cars were sold at Frank's Auto Corner during the second quarter of 1999? How many more cars were sold during the second quarter in 1999 than in the second quarter of 1998? Explain how you got your answer.
Mathematics
1 answer:
scZoUnD [109]1 year ago
8 0
Because I’m smart why are all the teachers doubting me I’m smartttt
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A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame
snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore,  length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be =  (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame -  area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

 3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula =\frac{-b\pm \sqrt{b^2-4ac}}{2a}, we get

=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}

x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)

x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)

We cant take negative value.

So, x=5\left(\sqrt{71}-6\right)=12.13

We could take approximately 12 cm.



7 0
2 years ago
a scientist wants to study 24 stars he studies 1/3 of them one week and 1/4 of them next week how many of them are left to study
zvonat [6]
6 because 1/3 of 24 is 8 and 1/4 of 8 is 6
4 0
2 years ago
The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in
Gnesinka [82]
First, determine the center of the circle by getting the midpoint of the points given for the circumference.
                    midpoint = ((0 + 0)/2, (3 + -4)/2)
                          midpoint (0, -0.5)
Then, we get the radius by determining the distance from either of the circumferential point to the center. 
                        radius = √(0 -  0)² + (3 +4)²  = 7
The equation for the circle would be,
                        x² + (y + 0.5)² = 7²
8 0
1 year ago
Which statement is true about the end behavior of the graphed function?
Tems11 [23]

Answer:

(SEE EXPLANATION FIRST)

Answer D is TRUE because on the graph if you were to keep going left even after the picture of the graph ends, the graph will still keep going up infinite

Step-by-step explanation:

If this is the graph you can read the answer

6 0
1 year ago
Read 2 more answers
Mr. mole left his burrow that lies 7 meters below the ground and started digging his way deeper into the ground, descending at a
Dimas [21]

Answer:

f(t)=-\frac{3}{2}t-7

Step-by-step explanation:

We know that:

  • The initial conditions are -7 meters at 0 minutes.
  • Then, after 6 minutes, he was 16 meters below the ground.

According to these two simple facts we can found the linear function that describes this problem. First, the problem says that Mr. Mole is descending at a constant rate, which is the slope of the function. Now, to calculate the slope we need to points, which are (0;-7) and (6;-16), where <em>t-values </em>are minutes, and <em>y-values </em>are meters. You can see, that the first point is the initial condition and the second point is 6 minutes later.

So, we calculate the slope:

m=\frac{y_{2}-y_{1}}{t_{2}-t_{1}} \\m=\frac{-16-(-7)}{6-0}=\frac{-16+7}{6}=\frac{-9}{6}=\frac{-3}{2}

From the slope we can see that Mr. Mole is descending, because it has a negative sign. Also, the point (0;-7) is on the <em>y-axis</em>, because <em>t</em> is null, so -7 is part of the function. Therefore the function that describes this problem is:

f(t)=-\frac{3}{2}t-7

7 0
2 years ago
Read 2 more answers
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