(12 - 9) / 12 = (40 - x) / 40
3/12 = (40 - x) / 40
40(1/4) = 40 - x
10 = 40 - x
10 - 40 = -x
-30 = -x
30 = x <=== percent decrease from 40 to 30
X*y = 450
y = 1/2x
x(1/2x) = 450
1/2x^2 = 450
x^2 = 450 * 2
x^2 = 900
x = sqrt 900
x = 30
y = 1/2(30)
y = 15
so ur numbers are : x = 30 and y = 15...but I am not sure of ur answer choices.
Given:
On the first day, she drove 650 miles in 10 hours.
On the second day, she got a later start and drove 540 miles in 8 hours.
To find:
Difference between average speed of second day and first day.
Solution:
We know that,

On the first day, she drove 650 miles in 10 hours. So, the average speed is


So, the average speed on first day is 65 miles per hour.
On the second day, she got a later start and drove 540 miles in 8 hours.


So, the average speed on second day is 67.5 miles per hour.
Difference between average speed is

Therefore, the average speed on the second day is 2.5 miles per hour is faster than first day.
Use the fact that
to solve it.

Answer:
500 lb
Step-by-step explanation:
You have to make a proportion:

77 lb is part of the whole weight ( which we don't know) so 77 will go on top
The problem tells us that 15.4% of the total weight is pecans so 15.4 will go over 100 (since % are out of 100)

Then you cross multiply giving you: 7700 = 15.4x
then you divide 15.4 to both sides to isolate x which will give you 500