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Aleksandr [31]
2 years ago
5

The function f(x) = –10(x)(x – 4) represents the approximate height of a projectile launched from the ground into the air with a

n initial velocity of 40 meters per second. How long, from launch to landing, does the projectile stay in the air? 0 seconds 1 second 2 seconds 4 seconds
Mathematics
2 answers:
ankoles [38]2 years ago
7 0

Answer: 4 seconds is how long, 100% correct just got it right on the quiz.

sineoko [7]2 years ago
4 0
The height of the project becomes zero when it hits the ground which is also the total time at which the projectile stays in the air. Equating the function to zero:
-10(x)(x - 4) = 0
The roots of this quadratic equation are:
x = 0, and x=4

Therefore, the projectile stays in the air for
4 seconds

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Answer:

9.48*

Step-by-step explanation:

This is a right triangle. The formula for solving the Hypotenuse, or the longest side of the right triangle is A^2 + B^2 = C^2. If we put the numbers from the problem into the formula this is what we get :

3^2 + 9^2 = C^2

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* This is rounded, the exact number is closer to 9.486832980505138. Your class should tell you what to round to.

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2 years ago
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Savatey [412]
<span>The expression given (27x^2)z/(-3x^2)(z^6), can be simplify as below:

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<span>
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