One answer could be 2 as 2^2 is 4 and 2+2 also equals 4
Answer:
the probability the rock has raritanium is 0.9670
Step-by-step explanation:
These events have been defined as
Z: sample has raritanium
Y: the reading from detector is positive
Z': sample has no raritanium
Y': Reading from detector is negative
P(z) = 0.13
P(y'/z) = 0.02
P(y/z')= 0.005
We need to find p(z/y)
= p(z/y) = p(z ∩ y)/p(y)
= P(z) - p(z∩y)/0.13 = 0.02
Remember the value of p(z) = 0.13
So when we cross multiply we get
0.13 - p(z ∩ y) = 0.02 x 0.13
0.13 - p(z ∩ y) = 0.0026
-p(z ∩ y) = 0.0026 - 0.13
Such that
p(z ∩ y) = 0.1274
P(y/z')= 0.005
P(z∩y') = 0.005
Since p(z) = 0.13
P(z') = 1-0.13
P(y) - p(z∩y)/0.87 = 0.005
We cross multiply
P(y) - 0.1274 = 0.005x0.87
P(y) = 0.1274+0.00435
P(y) = 0.13175
We have 0.1274/0.13175
= 0.9670
So we conclude that probability rock has raritanium is 0.9670
1=28:40 I don't know about the rest
Answer:
Step-by-step explanation:
A dime is worth 10 cents. Converting to dollars, it becomes 10/100 = $0.1
A quarter is worth 25 cents. Converting to dollars, it becomes 25/100 = $0.25
Let x represent the number of dimes that Jayden has.
Let y represent the number of quarters that Jayden has.
Jayden has some dimes and some quarters. He has at most 25 coins. It means that
x + y ≤ 25
The coins worth at least $4.60 combined. It means that
0.1x + 0.25y ≥ 4.6 - - - - - - - - - - 1
If Jayden has 7 dimes, then
7 + y ≤ 25
y ≤ 25 - 7
y ≤ 18
Substituting x = 7 into equation 1, it becomes
0.1 × 7 + 0.25y ≥ 4.6
0.7 + 0.25y ≥ 4.6
0.25y ≥ 4.6 - 0.7
0.25y ≥ 3.9
y ≥ 3.9/0.25
y ≥ 15.6
All possible values for the number of quarters that he could have would be
15.6 ≤ y ≤ 18
