The table shows the results of four surveys that randomly sampled 30 teenagers about their favorite night to hang out with frien
ds. Friday Saturday Sunday Total Survey 1 9 14 7 30 Survey 2 11 13 6 30 Survey 3 10 14 6 30 Survey 4 7 5 18 30 Identify surveys that are likely biased. Based on the unbiased surveys, what percent of the teenagers are likely to prefer hanging out with their friends on Saturday night? 21 % 34 % 38 % 46 %
2 answers:
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Answer:
11.51% probability that the mean annual salary of the sample is between $71000 and $73500
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
What is the probability that the mean annual salary of the sample is between $71000 and $73500?
This is the pvalue of Z when X = 73500 subtracted by the pvalue of Z when X = 71000. So
X = 73500
By the Central Limit Theorem
has a pvalue of 0.1151
X = 71000
has a pvalue of 0.
0.1151 - 0 = 0.1151
11.51% probability that the mean annual salary of the sample is between $71000 and $73500