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2 years ago

8

Joshua is doing a chemistry experiment that calls for a 30% solution of copper sulfate. He has 40ml of 25% solution. How many mi

llimeters of 60% solution should joshua add to obtain the required 30% solution?

1 answer:

Sholpan [36]2 years ago

8 0

Answer:

6 2/3 mL

Step-by-step explanation:

Multiply thru by 100 to get:

1000 + 60x = 30*40 + 30x

30x = 200

x = 6 2/3 mL (amt. of 60% solution needed in the mixture)

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Eric works for an airline, and he needs to calculate the weight of passengers and luggage before takeoff. The number of

igomit [66]

Answer:

B

Step-by-step explanation:

To complete the question, here are the answer choices:

<em>A) =A1*A2*A3*A4 </em>

<em>B) =A1*A2+A3+A1*A4 </em>

<em>C) =A1*(A2+A3+A1)*A4 </em>

<em>D) =A1*A2+(A3+A1)*A4</em>

<em />

We first need to multiply A1 and A2, this will give weight of passengers.

To get weight of luggage, we multiply A1 and A4.

We also need the checked weight to add to that, which is in A3. So then we add up A3 with those 2.

So we will get

A1*A2 + A1*A4 + A3

This is given in a different order in Option B. Hence, option B is right.

4 0

2 years ago

Read 2 more answers

EF is located at E (x,y) and F (7,-10) and was rotated around the origin. EF became E’F’ with coordinates E’ (4,5) and For (10,7

monitta

Answer:

90° CCW

Step-by-step explanation:

If we assume you intend F'(10, 7), point F has been transformed by the rule ...

(x, y) ⇒ (-y, x)

The transformation rule (x, y) ⇒ (-y, x) represents a 90° CCW rotation.

5 0

2 years ago

Counter example. The sum of three fractions with odd numerators is never 1/2

kolbaska11 [484]

1/6 + 1/6 + 1/6 = 3/6 = 1/2

8 0

2 years ago

Read 2 more answers

Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll

JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

$\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}$

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

$Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

So, the possibility of getting a total of 7 = $\frac{6}{36}=\frac{1}{6}$

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = $\frac{2}{36}$ = $\frac{1}{18}$

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = $\frac{28}{36}$ = $\frac{7}{9}$

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

$\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11$

$\frac{11}{3}+\frac{11}{3}-\frac{77}{9}$

$\frac{22}{3}-\frac{77}{9}$

$\frac{66-77}{9}$

$-\frac{11}{9}$

$-1.22$

Therefore the expected payoff for this game is -$1.22.

4 0

2 years ago

5 pies were shared equally among 6 girls. What fraction of a pie did each girl receive? Explain.

kompoz [17]

Answer:

Step-by-step explanation:

5/6

4 0

2 years ago