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olasank [31]
1 year ago
8

Joshua is doing a chemistry experiment that calls for a 30% solution of copper sulfate. He has 40ml of 25% solution. How many mi

llimeters of 60% solution should joshua add to obtain the required 30% solution?
Mathematics
1 answer:
Sholpan [36]1 year ago
8 0

Answer:

6 2/3 mL

Step-by-step explanation:

Multiply thru by 100 to get:

1000 + 60x = 30*40 + 30x

30x = 200

x = 6 2/3 mL (amt. of 60% solution needed in the mixture)

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The hawk flew over the meadow and saw 60 mice he caught 18 of them what percent of the mice did he catch
Irina-Kira [14]

Answer:

18%

Step-by-step explanation:

So there is 60 mice and he caught 18.

Convert it to a fraction (ratio)

So the answer is 18% for this question.

Hope this helps.

5 0
2 years ago
The function y = -0.03(x - 14)^2 + 6 models the mump of a red kangaroo where x is the horizontal distance in meters and y is the
Galina-37 [17]
The trick here is to find the vertex for its highest point and find the root that is of the greatest value for the final distance.

The nice thing about this function is that it has been written in what we call vertex form. This means that the maximum (or minimum if the parabola opens upwards) is given to us at the end of the function. In this case it is 6. We know that the graph starts at (0,0) (because the cangaroo jumps starting at no height with no distance so far) and so if the x-value given for the vertex is 14, we know that if we double that value, it will give us the second root. The total distance jumped is 28m.

Highest point: 6m
Total distance: 28m
3 0
1 year ago
Read 2 more answers
Please help. I am getting in trouble so please try to be correct...
vichka [17]

Answer: The answer is A 17in2

Step-by-step explanation:

In the question it states that the triangles are congruent (both the same).

  first I found the area of the top orange triangle.

the formula to find the area of a triangle is \frac{1}{2} bh (base times Height).

so I did  \frac{1}{2} 3.23* 5.12  which gave me 8.27.

Since the triangles are congruent (the same) they would both have the same area along with base and height. so I multiplied 8.27 by 2 (because there are two triangles) and got 16.54 which rounds up to 17.

the question also stated to find the APPROXIMATE area (close to the actual, but not completely accurate or exact.)

7 0
1 year ago
Write a word problem that can be solved by ordering three decimals to thousandths. Include a solution
nikklg [1K]
Then make up a word problem that you can use decimals in.
6 0
1 year ago
One of the vertices of △PQR is P(2, −1). The midpoint of PQ is M(3, 0). The midpoint of QR is N(5, 3). Show that MN || PR and MN
VLD [36.1K]

Answer:

<em>See the proof below</em>

Step-by-step explanation:

Given the following coordinates

P(2, −1)

Midpoint of PQ M(3, 0)

We can get the coordinate point Q using the midpoint formula;

M(X,Y) = (x1+x2/2, y1+y2/2)

X = x1+x2/2

3 = 2+x2/2

6 = 2+x2

x2 = 6-2

x2 = 4

Y = y1+y2/2

0 = -1+y2/2

0 = -1 + y2

y2 = 0+1

y2 = 1

<em>Hence the coordinate of Q is (4, 1)</em>

Next is to get the coordinate of R

Given the midpoint of QR to be N(5, 3)

(5,3) = (4+x2/2, 1+y2/2)

5 = 4+x2/2

10 = 4+x2

x2 = 10-4

x2 = 6

1+y2/2 = 3

1+y2 = 6

y2 = 6-1

y2 = 5

<em>Hence the coordinate of R is (6,5)</em>

<em></em>

Given the coordinates M(3, 0) and N(5, 3)

Slope is expressed as:

m = y2-y1/x2-x1

m = 3-0/5-3

m = 3/2

Slope of MN = 3/2

Get the slope of PR

Given the coordinates P(2, −1) and R (6,5)

Slope of PR = 5-(-1)/6-2

Slope of PR = 5+1/4

Slope of PR = 6/4 = 3/2

<em>Since the slope of MN is equal to that of PR, hence MN is parallel to PR i.e MN || PR</em>

<em></em>

To show that MN = 1/2PR, we will have to take the distance between M and N and also P and R first as shown:

For MN with coordinates  M(3, 0) and N(5, 3)

MN = √(x2-x1)²+(y2-y1)²

MN = √(5-3)²+(3-0)²

MN = √2²+3²

MN = √13

Get the length of PR where P(2, −1) and R (6,5)

PR = √(6-2)²+(5+1)²

PR = √4²+6²

PR = √16+36

PR = √52

PR = √4*13

PR = √4*√13

PR = 2√13

Since MN = √13

PR = 2MN

Divide both sides by 2

PR/2 = 2MN/2

PR/2 = MN

Hence MN = 1/2 PR (Proved!)

8 0
1 year ago
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