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BlackZzzverrR [31]

1 year ago

13

For a school drama performance, student tickets cost $5 each and adult tickets cost $10 each. The sellers collected $3,570 from

512 tickets sold. If c is the number of student tickets sold, which equation can be used to find the amount of tickets sold of each type?

2 answers:

Gre4nikov [31]1 year ago

8 0

5c+10a=3570 c+a=512 ... a=512-c so ... 5c + 10(512-c)=3570

AlladinOne [14]1 year ago

8 0

Answer:

The system of equations is equal to

$a+c=512$

$5c+10a=3,570$

The number of adult tickets sold is $a=202\ tickets$

The number of student tickets sold is $c=310\ tickets$

Step-by-step explanation:

Let

c------> the number of student tickets sold

a-----> the number of adult tickets sold

we know that

$a+c=512$ -----> equation A

$5c+10a=3,570$ -----> equation B

Using a graphing tool

The solution of the system of equations is the intersection point both graphs

see the attached figure

The intersection point is $(202,310)$

therefore

the solution is

the number of adult tickets sold is $a=202\ tickets$

the number of student tickets sold is $c=310\ tickets$

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