Question

For a school drama performance, student tickets cost $5 each and adult tickets cost $10 each. The sellers collected $3,570 from 512 tickets sold. If c is the number of student tickets sold, which equation can be used to find the amount of tickets sold of each type?

Answer 1

5c+10a=3570 c+a=512 ... a=512-c so ... 5c + 10(512-c)=3570

Answer 2

Answer:

The system of equations is equal to

$a+c=512$

$5c+10a=3,570$

The number of adult tickets sold is $a=202\ tickets$

The number of student tickets sold is $c=310\ tickets$

Step-by-step explanation:

Let

c------>  the number of student tickets sold

a----->  the number of adult tickets sold

we know that

$a+c=512$ -----> equation A

$5c+10a=3,570$ -----> equation B

Using a graphing tool

The solution of the system of equations is the intersection point both graphs

see the attached figure

The intersection point is $(202,310)$

therefore

the solution is

the number of adult tickets sold is $a=202\ tickets$

the number of student tickets sold is $c=310\ tickets$