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coldgirl [10]
2 years ago
6

Mathew rolls a number cube labeled with the numbers 1−6. He then flips a fair coin. What is the probability that he rolls a 4 an

d flips a head?
Mathematics
2 answers:
Lera25 [3.4K]2 years ago
6 0

Answer:

1/12

Step-by-step explanation:) on ED

kap26 [50]2 years ago
3 0

Answer: 0.083


Step-by-step explanation:

Numbers on cube=6

faces on coin=2

Therefore, the total outcomes=6\times2=12

Now, the favorable outcome that he rolls a 4 and flips a head=1

The probability that he rolls a 4 and flips a head=\frac{\text{favorable outcome}}{\text{total outcome}}

⇒The probability that he rolls a 4 and flips a head=\frac{1}{12}=0.083333\approx0.83.

Therefore, The probability that he rolls a 4 and flips a head=0.083

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Answer:

The total length of the trip was 400 miles.

Step-by-step explanation:

He fell asleep at 44% through the trip, they already had traveled 176 miles.

.44x = 176 ⇒

176 ÷ .44 ⇒

x = 400

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2 years ago
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You are a pharmacy technician. You need to prepare a 0.85-gram dose of a liquid antibiotic. The medicine is concentrated at 250
Xelga [282]

Answer:

17mL

Step-by-step explanation:

Convert 0.85 gr to miligrams

If 100 mg is 1 gr. Then, 0.85 gr is 850 mg

So, 850 multiply for 5ml and divide for 250 ml

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A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye
natita [175]

Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

=2000(1+0.0025)^12

=2000(1.0025)^12

=2000(1.0304)

=$2060.8

After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

=2060.8(1+0.0025)^24

=2060.8(1.0025)^24

=2060.8(1.0618)

=$2188.157

After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

=2188.157(1+0.0025)^36

=2188.157(1.0025)^36

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8 0
2 years ago
Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para
kvasek [131]

Answer:

(a) 0.932

(b) 0.0653

(c) 0.032

(d) 0.316

(e) 0.251

Step-by-step explanation:

From the table with mean parameter μ = 5, we can compute the following cumulative and density probability

(a) P(X \leq 8) = 0.932 (cumulative)

(b) P(X = 8) = 0.0653 (density)

(c) P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032 (cumulative)

(d) P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316 (cumulative)

(e) P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251

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2 years ago
Multiply<br> Express your answer in simplest form<br> Next
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