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Neko [114]
1 year ago
8

A potter works 4 days a week, makes 14 pots per day on average, and charges $24 a pot. If she lowers her price to $16 a pot, by

how many pots per day on average must she increase her production to make the same amount of money per 4-day workweek?
Mathematics
2 answers:
iragen [17]1 year ago
5 0

Hello!

Your answer is 7.

Toodles~

Taya2010 [7]1 year ago
3 0

Answer:

7 pots per day.

Step-by-step explanation:

A potter works 4 days a week, makes 14 pots per day and charges $24 a pot.

She earns =

4 (days) × 14 (pots) × 24 (charge) = $1,344

Now we have to find out number of pots production per day to make the same amount in a week, if she lowers her price to $16.

Let the number of pots now be x

Therefore,

$1,344 = (4) (x) (16)

1,344 = 64x

x = 1,344 ÷ 64

x = 21 pots per day

She already makes 14 pots. so the increment of the making pots would be

21 - 14 = 7 pots.

She must increase her production of 7 pots per day to make the same amount.

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1 year ago
The Parker family drove a total of 180 miles on the road trip. This distance is 1.5 times the distance they drove on the first d
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Parker family drove 120 miles on the first day

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Total miles driven on the road trip= 180 miles

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1 year ago
Isabella saved 2 nickels today. If she doubles the number of nickels she saves each day, how many days, including today, will it
luda_lava [24]

Answer:

Step-by-step explanation:

Alright, lets gets started.

First day, she saves nickels = 2

As we know, she doubles the number of nickels she saves each day.

Means second day she saves nickels = 2*2 = 4

Third day she saves nickels = 2*4 = 8

Fourth day she saves nickels = 2*8=16

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It is like a geometric series, the sum of nickels she needs more than 500.

So, lets see how many days she will take to save 500 nickels first

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s=\frac{a(1-r^n)}{(1-r)}

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Simplifying, dividing 2 in both sides

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Cross multiplying

-250=1-2^n

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2^n=251

Taking log on both sides

nlog2=log251

n=\frac{log251}{log2}=7.971

It means it will take 8 days to save mmore than 500 nickels.   :  Answer

Hope it will help :)


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