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antoniya [11.8K]
2 years ago
15

Ramona had 8 3/8 in. of ribbon. She used 2 1/2 in. for an art project.How many inches of ribbon does she have left?

Mathematics
2 answers:
disa [49]2 years ago
8 0
8\frac{3}{8}= \frac{67}{8}

2\frac{1}{2} = \frac{5}{2} = \frac{20}{8}

\frac{67}{8}-  \frac{20}{8} = \frac{47}{8} =5 \frac{7}{8} in
muminat2 years ago
6 0

Answer: There is 5\frac{7}{8}\ in. left.

Step-by-step explanation:

Since we have given that

Length of ribbon Ramona had is given by

8\frac{3}{8}=\frac{67}{8}\ in.

Length of ribbon she used for a project is given by

2\frac{1}{2}=\frac{5}{2}\ in.

Number of inches of ribbon left is given by

\frac{67}{8}-\frac{5}{2}\\\\=\frac{67-20}{8}\\\\=\frac{47}{8}\ in\\\\=5\frac{7}{8}\ in.

Hence, there is 5\frac{7}{8}\ in. left.

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Answer:

Option (D)

Step-by-step explanation:

Given polynomial is,

2x³ - 3x² - 3x + 2

If (x - 2) is the factor of the given polynomial,

By synthetic division we can get the other factor.

2 |  2     -3       -3       2    

 

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Therefore, other factor of the given polynomial is (2x² + x - 1)

Now (2x² + x - 1) = 2x² + 2x - x - 1

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Therefore, factors of the given polynomial other than (x - 2) are (2x - 1) and (x + 1)

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4 0
2 years ago
In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t
victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is   p =\frac{1}{5}

The correct answer choice is

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b

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The standard deviation is \sigma=4

c

The probability, P =0.0002

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability Pe = 0.0003

The probabilities P \approx Pe

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

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substituting the value

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The standard deviation is mathematically represented as

         \sigma = \sqrt{np (1-p)}

substituting the value

           = \sqrt{100 * 0,2 (1-0.2)}

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Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

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By standardizing the normal approximation we have that

              P(X \ge 34) \approx P(Z \ge z)

Now z is mathematically evaluated as

               z = \frac{x-\mu}{\sigma }

Substituting values

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The probability P and Pe that 34 or more subject would choose the center pair is very small  So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

 

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