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antoniya [11.8K]
2 years ago
15

Ramona had 8 3/8 in. of ribbon. She used 2 1/2 in. for an art project.How many inches of ribbon does she have left?

Mathematics
2 answers:
disa [49]2 years ago
8 0
8\frac{3}{8}= \frac{67}{8}

2\frac{1}{2} = \frac{5}{2} = \frac{20}{8}

\frac{67}{8}-  \frac{20}{8} = \frac{47}{8} =5 \frac{7}{8} in
muminat2 years ago
6 0

Answer: There is 5\frac{7}{8}\ in. left.

Step-by-step explanation:

Since we have given that

Length of ribbon Ramona had is given by

8\frac{3}{8}=\frac{67}{8}\ in.

Length of ribbon she used for a project is given by

2\frac{1}{2}=\frac{5}{2}\ in.

Number of inches of ribbon left is given by

\frac{67}{8}-\frac{5}{2}\\\\=\frac{67-20}{8}\\\\=\frac{47}{8}\ in\\\\=5\frac{7}{8}\ in.

Hence, there is 5\frac{7}{8}\ in. left.

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Fred wants to find 48+34 using compensation.He says you can take 2 from 34 and give it to 48 to make 50.What is the sum?Explain
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It is easier to add 50 to a number than 48 because 50 has a zero in it which makes an addition simpler.

48 + 34 =     borrow 2 from 34 and add to 48

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2 years ago
The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c
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\text{Answer} : \text{The expected value of a t-shirt is \$31.}

Explanation:

Since we have given that

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As we know that,

E(X)= \sum_{1}^{3}x_iP(x_i)

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Now,

x_1= \$24 , x_2=\$30 , x_3=$36

and

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So,

E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31

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barxatty [35]

Answer:

Neither are correct.

Step-by-step explanation:

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