Find a counter example. The product of any integer and 2 is greater than 2

1 answer:

8 0

Examples:

   3 x 2 = 6

   7 x 2 = 14

   Both are greater than 2 .

Counter examples:

      1 x 2 =   2

   -6 x 2 = -12

Not greater than 2 .

You might be interested in

Jim Ryan, an owner of a Burger King restaurant, assumes that his restaurant will need a new roof in 7 years. He estimates the ro

Lelu [443]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$9000\\
P=\textit{original amount deposited}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &7
\end{cases}
\\\\\\
9000=P\left(1+\frac{0.06}{4}\right)^{4\cdot 7}\implies 9000=P(1.015)^{28}\implies \cfrac{9000}{1.015^{28}}=P$

6 0

2 years ago

Triangle A B C is shown. Angle A C B is a right angle. The length of hypotenuse A B is 12 centimeters, the length of C B is 9.8

Paha777 [63]

Answer:

tan−1(StartFraction 6.9 Over 9.8 EndFraction)

Step-by-step explanation:

tan−1(StartFraction 6.9 Over 9.8 EndFraction)

tan = opp/adj = 9.8/6.9

tan -1 = 1 / tan = 1 / (9.8 /6.9) = 6.9 /9.8

4 0

2 years ago

Read 2 more answers

PLS HELP, 50 POINTS!!!

Sedaia [141]

Answer:

Part A: From 0 to 2 seconds, the height of the water balloon increases from 60 to 75 feet, therefore the water balloon's height is increasing during the interval [0,2]

Part B: From 2 to 4 seconds, the height of the water balloon stays the same at 75 feet, therefore the water balloon's height is the same during the interval [2,4] From 10 to 12 seconds, the height of the water balloon stays the same at 0 feet, therefore the water balloon's height is the same during the interval [10,12] From 12 to 14 seconds, the height of the water balloon stays the same at 0 feet, therefore the water balloon's height is the same during the interval [12,14]

Part C: The interval, [4,6] of the domain is when the water ballon's height decreases the fastest. The interval [4,6] decreases by 35 feet. The two other intervals that decrease are [6,8] and [8,10] which both have the same slope. They decrease by 20 feet. Therefore, this helps us conclude that the interval [4,6] decreases the fastest because 35 feet is a more significant decrease than 20 feet.

Part D: I predict that the height of the water balloon at 16 seconds is 0 feet. This is because at 10-14 seconds, the water balloon's height is 0 feet. In read-world situations, if the water balloon is on the ground which is 0 feet, it stays on the ground due to gravity.

Step-by-step explanation:

I hope this helps! I also do not know if it is all correct but I did research and everything so hopefully it is correct! Good luck!

8 0

2 years ago

Read 2 more answers

Find the volume of the following solid figure. Use = 3.14. V = 4/3r3. A sphere has a radius of 3.5 inches. Volume (to the neares

Juli2301 [7.4K]

To solve the problem shown above, you must apply the proccedure shown below:

1. You must use tthe formula for calculate the volume of a sphere, which is:

V=4πr³/3

V is the volume of the sphere.
r is the radius of the sphere (r=3.5 inches)

2. When you susbstitute these values into the formula shown above, you obtain the volume of the sphere. Therefore, you have:

V=4πr³/3
V=4π(3.5 inches)³/3

3. Therefore, the answer is:

V=179.5 inches³

4 0

2 years ago

Read 2 more answers

Rewrite the expression (3a^2b^3c^5)/(8x^4y^3z)so that it has no denominator. (note: do not use a fraction line in your answer. a

Gemiola [76]

Use:

$\dfrac{1}{a}=a^{-1}\\\\\dfrac{1}{a^n}=a^{-n}$

$\dfrac{3a^2b^3c^5}{8x^4y^3z}=3a^2b^3c^5\cdot8^{-1}x^{-4}y^{-3}z^{-1}$

Answer: 3"8^-1a^2b^3c^5x^-4y^-3z^-1

5 0

2 years ago

Read 2 more answers