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salantis [7]
2 years ago
13

A certain medicine is given in an amount proportional to a patient's body weight. Suppose a patient weighing 153 pounds requires

249 milligrams of medicine. What is the amount of medicine required by a patient weighing 102 pounds?
Mathematics
2 answers:
mario62 [17]2 years ago
7 0
Mg required per pound = 249/153 = 1.63mg

Therefore medicine required=  102 *1.63= 166.26g

Sonja [21]2 years ago
5 0

Answer: 166 milligrams

Step-by-step explanation:

Given : A certain medicine is given in an amount proportional to a patient's body weight.

A patient weighing 153 pounds requires 249 milligrams of medicine.

Let x be the amount of medicine required by a patient weighing 102 pounds, then we have the following equation:-

\dfrac{x}{102}=\dfrac{249}{153}\\\\\Rightarrow\ x=\dfrac{249\times102}{153}=166

Hence, the amount of medicine required by a patient weighing 102 pounds = 166 milligrams.

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Answer:

Step-by-step explanation:

A motorcycle has an initial speed of u m/s. It accelerates to a speed of 1.2u in 10 seconds

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S= ut + (1/2)at²

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S = u(10) + (1/2)(0.02)(10)²

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2 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
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Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

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2. Observe that

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  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

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and the analysis for be transitive is the same that we did in a).

Observe that

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  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
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Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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  • 3 must be related with 3,
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For be symmetric

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For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
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Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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