Answer:

So then P =11000 is the minimum that the least populated district could have.
Step-by-step explanation:
We have a big total of N = 132000 for the population.
And we know that we divide this population into 11 districts
And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"
Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P
The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:


So then P =11000 is the minimum that the least populated district could have.
You do three fourths times eight and that equals six.
Answer:
It was a sappy one
Step-by-step explanation:
lol
Answer:
a) P = 0.039
b) The expected number of days is 10 days.
Step-by-step explanation:
The most appropiate distribution to use in this case is the geometric distribution, in order to calculate the probability of a success after k failure trials.
The probability of success, as each of the 10 products are assumed to have fair probabilities, is:

Then, the probability that our product is not selected any given day is:

a) The probability that exactly this product is selected exactly 10 days from now is the probability that is not selected (probbility q) for the next 9 days and selected (probability p) at the 10th day:

b) The expected number of days is calculated as:
