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ruslelena [56]
2 years ago
13

PQ= 2x +1 and QR= 5x - 44; find PQ

Mathematics
2 answers:
Lena [83]2 years ago
6 0

2x+1=5x-44 that would be your equation

next start to simplify 

subtract 1 from both sides so you are left with 2x=5x-45

then subtract 5x from both sides and you have -3x=-45

then finally divide -3 from -45 to get x=15

vova2212 [387]2 years ago
6 0

Answer:

PQ=31\ units

Step-by-step explanation:

we know that

In this problem Q is the midpoint of PR

so

PQ=QR

we have

PQ=2x+1 -----> equation A

QR=5x-44 -----> equation B

equate equation A and equation B

2x+1=5x-44

solve for x

5x-2x=1+44

3x=45

x=15

Find the value of PQ

PQ=2x+1 ------> PQ=2(15)+1=31\ units

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4 lines are shown. A line with points T, R, W intersects a line with points S, R, V at point R. Another line extends from point
lianna [129]

Answer:

The Answer is B

Step-by-step explanation:

Edgenuity ;)

4 0
2 years ago
The half-life of carbon-14, 14C, is approximately 5,730 years. A bone fragment is estimated to have originally contained 6 milli
anzhelika [568]

Answer:

A(t)=6\cdot2^{-\frac{t}{5730 }

Step-by-step explanation:

The general formula for exponential decay given a half-life t_\frac{1}{2} is

N(t)=N_{0}\cdot2^{\frac{-t}{t_{1/2} }      

where N(t) is the amount at time t, N_0 is the initial amount (at time t=0), and t_\frac{1}{2} is the half life of the substance.

The half life of carbon-14, is approximately 5,730 years.

t_\frac{1}{2} = 5730 years

N_0= 6 milligrams

Therefore:

Amount of carbon-14 remaining in the bone fragment after t years is:

A(t)=6\cdot2^{-\frac{t}{5730 }

6 0
2 years ago
Let f(x) represent a function. Which descriptions match the given transformations? Drag and drop the answers into the boxes.
miss Akunina [59]

The correct answers are:

1. f (x) is translated 4 units down.

2. f (x) is vertically stretched by a factor of 4.

I took the quiz and these were the right answers. Hope I helped! <3

8 0
2 years ago
Read 2 more answers
An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

4 0
2 years ago
. Over the next two days, Clinton Employment Agency is interviewing clients who wish to find jobs. On the first day, the agency
Vedmedyk [2.9K]

Answer:

4

Step-by-step explanation:

Given that :

Clients are interviewed in groups of 2 on the first day; meaning two persons at a time

Second day, clients are interviewed in groups of 4; meaning 4 persons at a time.

Therefore, if the same number of clients are to be interviewed on each day, the smallest number of clients that could be interviewed each day could be obtained by getting the Least Common Multiple of both numbers: 2 and 4

- - - - 2 - - - 4

2 - - - 1 - - - 2

2 - - - 1 - - - 1

Therefore, the Least common multiple is (2 * 2) = 4

Therefore, the smallest number of clients that could be interviewed each day is 4.

5 0
2 years ago
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