Answer:
B) Interquartile range
Step-by-step explanation:
Since there are some students that do not eat fast food at all, their amounts spent monthly would be $0. These are much different than the rest of the data, and thus are outliers.
Outliers can greatly affect the mean. This tells us the mean may not be the best measure.
Since the mean is affected by outliers, the standard deviation is not the best measure either.
Adding data points of 0 will also affect the range. This leaves the interquartile range as the better measure.
For this case we define the following variables:
x: Number of party dresses
y: Number of suits
You have 30 hours per week to cut, that is, the first equation is given by:
It is also known that 25 hours per week are available for sewing, that is:
It has a system of two equations with two unknowns, solving we have:
Multiplying the second equation by -1:
Adding up:
Substituting x in the first equation:
Clearing and:
Thus, per week, the designer can produce 5 party dresses and 5 suits working at her maximum capacity.
Answer:
5 Party dresses
5 Suits
The minimum number of times two planes can intersect is zero, because if the planes are parallel to each other, they will never intersect. we can take the example of floor and roof, both are parallel to each other and no intersection. If the two planes are in same plane the maximum number of times they can intersect is infinite for example if we consider a line we can intersect at infinite points.
Answer: the boy won 10 games
Step-by-step explanation:
Let's call B as the number of games won by the boy, and F as the number of games won by the father.
We know that, there is a total of 26 games:
B + F = 26.
We know that in each game won by the boy, he wins 8 cents, for every game that the father wins, the boy losses 5 cents, and we know that at the end of the 26 games, the boy did not win or lose any money, so we have:
B*8 + F*(-5) = 0.
Then we have a system of equations:
B + F = 26
8*B - 5*F = 0.
The first step is isolating one of the variables. Let's start isolating F in the first equation:
B + F = 26
F = 26 - B.
Now we can replace this in the second equation:
8*B - 5*F = 0
8*B - 5*(26 - B) = 0
8*B + 5*B - 5*26 = 0
13*B = 5*26
B = 5*26/13 = 5*2 = 10
So the boy won 10 games (then the father won the other 16 games)
