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2 years ago

Select the two figures that are similar to the 9 by 6 figure that’s is shown.

Mathematics

2 answers:

harina [27]2 years ago

5 0

Answer:

the answer is green and yellow

Step-by-step explanation:

if youre from ttm here you go

Eduardwww [97]2 years ago

3 0

Answer:

The correct option is 3. The green figure is similar to the 9 by 6 figure.

Step-by-step explanation:

Let a small square represents 1 unit.

From the given figure it is noticed that

1. The dimensions of red figure is 4 by 3.

2.The dimensions of brown figure is 4 by 6.

3.The dimensions of green figure is 2 by 3.

3.The dimensions of purple figure is 3 by 6.

The dimensions of given figure is 9 by 6. The proportion of its dimensions is

$\frac{9}{6}=\frac{3}{2}$

The corresponding sides of two similar figure are proportional. It means the ration of sides must be $\frac{3}{2}$ .

The dimensions of green figure is 2 by 3. It means the proportion of its dimensions is $\frac{3}{2}$ .

Therefore the correct option is 3. The green figure is similar to the 9 by 6 figure.

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Ivanna is playing a game in which she spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a num

saul85 [17]

Answer:

The spinner has 6 equal-sized slices, so each slice has a 1/6 probability of showing up.

I guess that we want to find the expected value in one spin:

number 1: wins $1

number 2: wins $3

number 3: wins $5

number 4: wins $7

number 5: losses $8

number 6: loses $8

The expected value can be calculated as:

Ev = ∑xₙpₙ

where xₙ is the event and pₙ is the probability.

We know that the probability for all the events is 1/6, so we have:

Ev = ($1 + $3 + $5 + $7 - $8 - $8)*(1/6) = $0

So the expected value of this game is $0, wich implies that is a fair game.

8 0

2 years ago

Assume the blood pressures of 10 people were measured before and after sleeping for the night. What is the corresponding critica

NeX [460]

Answer:

For the critical value we need to calculate the degrees of freedom given by:

$df = n-1= 10-1=9$

And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:

$|t_{crit}| =1.833$

Step-by-step explanation:

Previous concepts

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

x=test value with right arm , y = test value with left arm

The system of hypothesis for this case are:

Null hypothesis: $\mu_y- \mu_x = 0$

Alternative hypothesis: $\mu_y -\mu_x \neq 0$

The first step is calculate the difference $d_i=y_i-x_i$

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{361}{5}$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}$

The 4 step is calculate the statistic given by :

$t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}$

For the critical value we need to calculate the degrees of freedom given by:

$df = n-1= 10-1=9$

And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:

$|t_{crit}| =1.833$

5 0

2 years ago

C. Assessment

Crazy boy [7]

1. B
2. A
3. A
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4 0

2 years ago

The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau

AleksandrR [38]

Answer:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$