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baherus [9]
2 years ago
5

For a sample of 100 students, the median number of text messages sent per day is 90, the first quartile is 78, and the third qua

rtile is 102. Select all of the answers that create a true statement.
Approximately 25 students in the sample send

more than 90 text messages.
less than 90 text messages.
more than 78 text messages.
more than 102 text messages.
between 90 and 102 text messages.
less than 78 text messages.
between 78 and 102 text messages.
Mathematics
2 answers:
ohaa [14]2 years ago
5 0


Approximately 25 students send
Less than 78 text messages
More than 102 text messages
slavikrds [6]2 years ago
4 0

Answer with explanation:

Q={\text{Median}}=90\\\\Q_{1}=78\\\\Q_{3}=102

There are 100 students in the group.

If we divide 100 students into groups

→First quartile =25.5

means, first quartile of students has median value ≤ 78.

→Median =50.5

Most of the students sends ,90 messages a day.

→Third Quartile=75.5

Students lying above the third Quartile ,sends ≥102 messages per day.

First Quartile means, approximately 0- 25 students in the group , sends 78 messages.

Q_{1}\leq 78

Third Quartile means, 75-100 , students in the group, sends 102 messages .

Q_{3}\geq 102

Approximately 25 students in the sample send

1. more than 102 text messages.

2.less than 78 text messages.

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Step-by-step explanation:

×=100

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2

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6 0
2 years ago
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An engineer is designing an arch-shaped gate for the entrance to an amusement park. The gate must be 80 feet wide and 25 feet ta
Tom [10]
1) the form of the equation may be written as y = A(X - Xo)(X - X1)

Where Xo and X1 are the two roots of the equation.


2) We can fix the system of coordinates so that the vertex is in the middle of the gate => Xo = - 40 and X1 = +40


=> y = A (X + 40) (X - 40) = A (X^2 - 1600) 


3) The height, at X = 0 is 25

=> A(0 - 1600) = 25


=> -1600A = 25 => A = -25 / 1600 = - 1/64


4) The equation is y =  - [1/64] (X^2 - 1600)


5) You can present it in different equivalent forms.

Some of those other forms are:

1) - 64y = (x^2 - 1600)

2) x^2 = - 64y + 1600

3) X^2 = - 64 (y - 25)
4 0
2 years ago
The mean of a list of 80 numbers is 230. If four numbers 145,156,210, and 255 are added, what is the mean of the list of numbers
anygoal [31]
Add 145, 156, 210. and 255 then divide by 4. The mean equals 184. 
7 0
2 years ago
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Alonso went to the market with \$55$55dollar sign, 55 to buy eggs and sugar. He knows he needs a package of 121212 eggs that cos
Neko [114]

Answer: See explanation

Step-by-step explanation:

Based on the scenario in the question, the expression to calculate the number of boxes of sugar Alonso can buys will be:

= 2.75 + 11.50S ≤ 55

When solved further, this will be:

2.75 + 11.50S ≤ 55

11.50S ≤ 55 - 2.75

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3 0
2 years ago
A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
amid [387]

Answer:

The correct conclusion is:

<em>"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."</em>

Step-by-step explanation:

A doctor is measuring the average height of male students at a large college.

The doctor measures the heights, in inches, of a sample of 40 male students from the baseball team.

Using this data, the doctor calculates the 95% confidence interval (63.5, 74.4).

The following conclusions is valid:

<em>"The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches."</em>

Since we know that the confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.  

For the given case, the confidence level is 95% and the corresponding confidence interval is (63.5, 74.4) which represents the true mean of heights for male students at the college where the doctor measured heights.

Therefore, it is valid to conclude that the doctor is 95% confident that the mean height of male students at the college is within the interval of (63.5, 74.4).

6 0
2 years ago
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