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Mnenie [13.5K]
2 years ago
7

If 35% of a natural area is to be developed, leaving 500 acres untouched, how many acres are to be developed?

Mathematics
2 answers:
xxTIMURxx [149]2 years ago
8 0
Given that the 35% of area has been developed, the percentage of land that has not been developed is:
100-35
=65%
hence the acres of land that are to be developed will be:
35/65*500
=269.23 acres
the answer is 269.23
harkovskaia [24]2 years ago
5 0

Answer:

Area to be developed = 269.23 acres

Step-by-step explanation:

Let there is A acres natural area to be developed.

If 35% of A acres is developed then untouched area will be (100 - 35 = 65%)

Now it has been given in the question that 65% of A (untouched area) = 500 acres

A.\frac{65}{100}=500

A=\frac{500}{0.65}=769.23

So area of the natural field = 769.23 acres

Now 35% of the natural area which is to be developed = A×35%

=769.23.\frac{35}{100}=(769.23)(.35)=269.23

Area of the natural area to be developed is 269.23 acres

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fomenos

Step-by-step explanation:

Since f(0) = f(5) = f(8) = 0, we have f(x) = Ax(x - 5)(x - 8), where A is a real constant.

We know that f(10) = 17.

=> A(10)(10 - 5)(10 - 8) = 17

=> A(10)(5)(2) = 17

=> 100A = 17, A = 0.17.

Hence the answer is f(x) = 0.17x(x - 5)(x - 8).

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1 year ago
A band director uses a coordinate plane to plan as how for a football game. During a show, the drummers will march along the lin
LenaWriter [7]

Answer:

The equation in slope-intercept form for the path of the trumpet players is y=\frac{x}{5}+\frac{12}{5}.

Step-by-step explanation:

Consider the provided information.

The drummers will march along the line y=-5x-8.

The trumpets players will march along a perpendicular line that passes through (-2,2).

The slope of line y=-5x-8 is: m₁ = -5.

The slope of perpendicular lines are: m_1\times m_2=-1

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Hence, the slope of the line should be 1/5.

The line passes through (-2,2).

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y-y_1=m(x-x_1)

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A line contains the points (82, −96) and (87, −86).
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Answer:

<h2>The answer is 2</h2>

Step-by-step explanation:

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<h3>2 </h3>

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