Answer:
The anwerss to the question are
(A) P(No less than two people use their phones while driving) = 0.1225
(B) P(The probability that no more than one person of the three people use their cell phone while driving) = 0.147875
Step-by-step explanation:
The given relations are
Percentage of motorists that routinely drive while sing their phone = 35 %
The probaboloty that if a peerson is random;ty selected from a group of hudred person routinely uses their phone wjile friving P(phone) = 35
The probability that a motorist randomly selected fron a set of 100 do not routinely use thir phones while driving = P(No celll phone) = 65
Then the probability that when three people are selected at random at least two people of the three people use their cell phone while driving is
P(phone) = 35/100m = 0.35
P(No celll phone) = 65/100 = 0.65
(A) Probability of at least two of three use their phones whle driving is
0.35×0.35×0.65 +0.35×0.35×0.35 = 0.1225
(B) The probability of only one person out of three seted use their phones while driving is
(0.35)(0.65)(0.65) = 0.147875
Answer:
Therefore, we use the linear depreciation and we get is 17222.22 .
Step-by-step explanation:
From Exercise we have that is boat $250,000.
The straight line depreciation for a boat would be calculated as follows:
Cost boat is $250,000.
For $95,000 Deep Blue plans to sell it after 9 years.
We use the formula and we calculate :
(250000-95000)/9=155000/9=17222.22
Therefore, we use the linear depreciation and we get is 17222.22 .
Answer:
The range stays the same.
The domain stays the same.
Step-by-step explanation:
The function 
is an exponential function, where <em>a</em> is the coefficient, <em>b</em> is the base and <em>x</em> is the exponent.
The domain for this kind of functions is: All real numbers.
And the range is: (0,∞); this happen because the exponential functions are always positive when <em>a</em>>0.
Therefore, if the value of <em>a</em> is increased by 2, the domains will stay the same and the range will stay the same: (0,∞). The coefficient does not change the domain or the range if it keeps the same sign.
Answer:
56
Step-by-step explanation:
Given that there are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom.
The three candidates that receive the highest number of votes become candidates for a runoff election.
i.e. 3 persons out of 8 to be selected for becoming candidates for a runoff election.
Since order does not matter we use combinations here
3 persons out of 8 can be done in 8C3 ways
= 56
no of 3-candidate combinations possible are 56
3 times the product of 5 and b is reduced by 2
3*(5*b)-2
15b-2
