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1 year ago

Explain how complex fractions can be used to solve problems involving ratios

1 answer:

8 0

When you have ratios and some unknowns you can create complex fractions from them.Bring them to the same denominator and solve for X.

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Boris chooses three DIFFERENT numbers.

g100num [7]

Answer:

4, 5, 27.

Step-by-step explanation:

Let us find our numbers using given information.

Factors of 20 are: 1,2,4,5,10 and 20.

Let us try by taking number 4 and 5.

$36-(4+5)=36-9=27$

We can see that $3^{3} =27$

Now let us find sum of these numbers.

$4+5+27=36$

Therefore, numbers chosen by Boris will be 4, 5 and 27 as these numbers satisfies our all conditions.

6 0

2 years ago

Two standard dice are rolled and their face values multiplied. What is the probability that the product is prime or ends in 0?

Trava [24]

The answer is 10/36 or 27.77%
here’s the working out

8 0

2 years ago

The chart indicates the time, speed, and velocity of five runners.

Nuetrik [128]

<span>Garreth and Elisa ran together, Luigi and Jasmine went the same distance, and Logan and Jasmine have the same displacement in the opposite direction. This is the answer which is C</span>

5 0

2 years ago

Read 2 more answers

Kenny and Michael have scored points during a basketball game. Kenny has scored 13 points, and Michael has scored p points. Toge

Vikentia [17]

Michael scores 14 points.

4 0

1 year ago

Read 2 more answers

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

4 0

1 year ago