Question

What is the value of b and the missing symbol in Jamilla’s inequality?

Answer 1

Answer:

The answer for my question was also C..

Step-by-step explanation:

Answer 2

Answer:

$b=1, \geq$

Step-by-step explanation:

we know that

The absolute value function has two solutions

Observing the graph

the solutions are

$x\geq 1$ and $x\leq -3$

First solution (case positive)

assume the symbol of the first solution and then compare the results

$\left|x+b\right|\ge2$

$(x+b)\ge2$

$x\ge2-b$

$2-b=1\\b=2-1\\ b=1$

Second solution (case negative)

$-(x+b)\ge2$

Multiply by -1 both sides

$(x+b)\leq-2$

substitute the value of b and compare the results

$(x+1)\leq-2$

$x\leq-2-1$

$x\leq-3$ -------> is correct