The 4 marked x is 10 times greater than the 4 marked y. That is because it is one place in front of the other 4, making it 10 times greater. If you need any help with understand this, please let me know and I will further assist you on this question! Hope I was able to help.
114
1^3 + 1^3 + 4^3 = 1 + 1 + 64 = 66
99 - 66 = 33
33/3 = 11
1 + 1 = 2
I am not sure of the exact way to solve this....I just did it by trial and error
Why are there hearts and idk sorry :/
Answer:
42 feet.
Step-by-step explanation:
h=-10t² + 40t +2
The vertex of the quadratic function described by the equation is located at
t = -(40)/(2(-10)) = 2
Next is to find the value of height at t=2 will be
h = -10(2²) +40(2) +2 = -40 +80 +2 = 42feet
The maximum height is 42 feet.
Answer:
The overview of the given problem is outlined in the following segment on the explanation.
Step-by-step explanation:
The proportion of slots or positions that have been missed due to numerous concurrent transmission incidents can be estimated as follows:
Checking a probability of transmitting becomes "p".
After considering two or even more attempts, we get
Slot fraction wasted,
= ![[1-no \ attempt \ probability-first \ attempt \ probability-second \ attempt \ probability+...]](https://tex.z-dn.net/?f=%5B1-no%20%5C%20attempt%20%5C%20probability-first%20%5C%20attempt%20%5C%20probability-second%20%5C%20attempt%20%5C%20probability%2B...%5D)
On putting the values, we get
= ![1-no \ attempt \ probability-[N\times P\times probability \ of \ attempts]](https://tex.z-dn.net/?f=1-no%20%5C%20attempt%20%5C%20probability-%5BN%5Ctimes%20P%5Ctimes%20probability%20%5C%20of%20%5C%20attempts%5D)
= ![1-(1-P)^{N}-N[P(1-P)^{N}]](https://tex.z-dn.net/?f=1-%281-P%29%5E%7BN%7D-N%5BP%281-P%29%5E%7BN%7D%5D)
So that the above seems to be the right answer.