A disadvantage of the contention approach for LANs, such as CSMA/CD, is the capacity wasted due to multiple stations attempting
1 answer:
Answer:
The overview of the given problem is outlined in the following segment on the explanation.
Step-by-step explanation:
The proportion of slots or positions that have been missed due to numerous concurrent transmission incidents can be estimated as follows:
Checking a probability of transmitting becomes "p".
After considering two or even more attempts, we get
Slot fraction wasted,
=
On putting the values, we get
=
=
So that the above seems to be the right answer.
You might be interested in
The rejection region is give by
where the test statistics is given by
i.e.
Thus,
Using the statistical table, the level of the test is 0.04.
where the test statistics is given by
i.e.
Thus,
Using the statistical table, the level of the test is 0.04.
Let us see... ideally we would like to have all equations with the same exponent or the same base so that we can compare the rates. Since the unknown is in the exponent, we have to work with them. In general, ![x^(y/z)= \sqrt[z]{x^y}](https://tex.z-dn.net/?f=x%5E%28y%2Fz%29%3D%20%5Csqrt%5Bz%5D%7Bx%5Ey%7D%20)
.
Applying this to the exponential parts of the functions, we have that the first equation is equal to:
250*(![\sqrt[5]{1.45} ^t](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B1.45%7D%20%5Et)
)=250*(1.077)^t
The second equation is equal to: 200* (1.064)^t in a similar way.
We have that the base of the first equation is higher, thus the rate of growth is faster in the first case; Choice B is correct.
Applying this to the exponential parts of the functions, we have that the first equation is equal to:
250*(
The second equation is equal to: 200* (1.064)^t in a similar way.
We have that the base of the first equation is higher, thus the rate of growth is faster in the first case; Choice B is correct.