Question

There is a number between 100 and 115, such that if you find the sum of the cubes of the digits, subtract this sum from 99, divide the result by 3, and add the digits once more, you get 2. What is the number?
*How would I solve this?*

Answer 1

114

1^3 + 1^3 + 4^3 = 1 + 1 + 64 = 66
99 - 66 = 33
33/3 = 11
1 + 1 = 2

I am not sure of the exact way to solve this....I just did it by trial and error