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Softa [21]
1 year ago
12

There is a number between 100 and 115, such that if you find the sum of the cubes of the digits, subtract this sum from 99, divi

de the result by 3, and add the digits once more, you get 2. What is the number?
*How would I solve this?*
Mathematics
1 answer:
balandron [24]1 year ago
7 0
114

1^3 + 1^3 + 4^3 = 1 + 1 + 64 = 66
99 - 66 = 33
33/3 = 11
1 + 1 = 2

I am not sure of the exact way to solve this....I just did it by trial and error
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In the data set below what is the mean absolute deviation 41,56,38,45,55,51,52
saveliy_v [14]
All of these numbers are making me crazy
8 0
1 year ago
ALGEBRA Jake Duffy drove 12,568 miles
kirza4 [7]

Answer:

The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B  

Step-by-step explanation:

Given as :

The distance drove by Jack Duffy = d = 12,568 miles

The fixed costs totaled = $1,485.00

The variable cost totaled = $2,015.75

Let The cost per mile that Jack Duffy charge = $x cost per miles

Now, According to question

The totaled cost = The fixed costs + The variable cost

Or, The totaled cost = $1,485.00 + $2,015.75

I.e  The totaled cost = $3500.75

Now,

The cost per mile that Jack Duffy charge = \dfrac{\extrm Total cost}{\textrm Total Distance}

I.e x = \dfrac{3500.75}{12568}

∴ x = $0.278 per miles

So,The cost per mile that Jack Duffy charge = x = $0.278 per miles .

Hence,The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B  Answer

5 0
2 years ago
nikki backyard is in the shape of a rectangle. the length is 27 feet. The width is one-third the length plus 4 feet. write and e
PIT_PIT [208]

Answer:

A= Length x Width

A= 27 x (1/3 x 27 + 4)

A=27 x (9 + 4)

A= 27 x 13

A= 351

Step-by-step explanation:

ye

4 0
1 year ago
A pond forms as water collects in a conical depression of radius a and depth h. Suppose that water flows in at a constant rate k
Scrat [10]

Answer:

a. dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. πa² ≥ k/∝

Step-by-step explanation:

a.

The rate of volume of water in the pond is calculated by

The rate of water entering - The rate of water leaving the pond.

Given

k = Rate of Water flows in

The surface of the pond and that's where evaporation occurs.

The area of a circle is πr² with ∝ as the coefficient of evaporation.

Rate of volume of water in pond with time = k - ∝πr²

dV/dt = k - ∝πr² ----- equation 1

The volume of the conical pond is calculated by πr²L/3

Where L = height of the cone

L = hr/a where h is the height of water in the pond

So, V = πr²(hr/a)/3

V = πr³h/3a ------ Make r the subject of formula

3aV = πr³h

r³ = 3aV/πh

r = ∛(3aV/πh)

Substitute ∛(3aV/πh) for r in equation 1

dV/dt = k - ∝π(∛(3aV/πh))²

dV/dt = k - ∝π((3aV/πh)^⅓)²

dV/dt = K - ∝π(3aV/πh)^⅔

dV/dt = K - ∝π(3a/πh)^⅔V^⅔

b. Equilibrium depth of water

The equilibrium depth of water is when the differential equation is 0

i.e. dV/dt = K - ∝π(3a/πh)^⅔V^⅔ = 0

k - ∝π(3a/πh)^⅔V^⅔ = 0

∝π(3a/πh)^⅔V^⅔ = k ------ make V the subject of formula

V^⅔ = k/∝π(3a/πh)^⅔ -------- find the 3/2th root of both sides

V^(⅔ * 3/2) = k^3/2 / [∝π(3a/πh)^⅔]^3/2

V = (k^3/2)/[(∝π.π^-⅔(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝π^⅓(3a/h)^⅔)]^3/2

V = (k^3/2)/[(∝^3/2.π^½.(3a/h))]

V = (hk^3/2)/[(∝^3/2.π^½.(3a))]

The small deviations from the equilibrium gives approximately the same solution, so the equilibrium is stable.

c. Condition that must be satisfied

If we continue adding water to the pond after the rate of water flow becomes 0, the pond will overflow.

i.e. dV/dt = k - ∝πr² but r = a and the rate is now ≤ 0.

So, we have

k - ∝πa² ≤ 0 ---- subtract k from both w

- ∝πa² ≤ -k divide both sides by - ∝

πa² ≥ k/∝

5 0
2 years ago
The height of a cylinder is twice the radius of its base. A cylinder has a height of 2 x and a radius of x. What expression repr
cluponka [151]
<h2>Answer:</h2><h2>volume of the cylinder = 2πx^{3}</h2>

Step-by-step explanation:

The height of a cylinder is twice the radius of its base.

Let the height of the cylinder = 2x

Let the radius of the cylinder = x

By formula, volume of the cylinder = πr^{2} h

here r = x, h = 2x

substituting the values in the equation, we get

volume of the cylinder = πr^{2} h =  π x^{2} (2x)

volume of the cylinder = 2πx^{3}

5 0
2 years ago
Read 2 more answers
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