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Lynna [10]
2 years ago
6

Tonia and Trinny are twins.Their friends give them identical cakes for their birthday.Tonia eats 1/8 of her cake and Trinny eats

1/6 of her cake. How much cake is left?
Mathematics
1 answer:
Licemer1 [7]2 years ago
5 0

Answer: 7 over 24 I think so! Sorry I didn’t reduce

Step-by-step explanation:

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Square ABCD is shown below with line EF passing through the center: If Square ABCD is dilated by a scale factor of two about the
dlinn [17]
Line E'F' would also double.


3 0
2 years ago
You have a function that takes in an X value and produces a Y value. The Y value equals 24 times the X value, plus 4?More. What'
guapka [62]

Answer:

100

Step-by-step explanation:

The function takes in an X value and produces a Y value.

The Y value equals 24 times the X value plus 4 more.

This means that:

Y = 24X + 4

When the X value equals 4, the Y value will be:

Y = 24(4) + 4

Y = 96 + 4

Y = 100

When the X value is 4, the Y value is 100.

7 1
2 years ago
Read 2 more answers
Tiffany sells two kinds of homemade tomato sauce. A quart of her Tuscan sauce requires 6 tomatoes and 1 cup of oil. A quart of h
jok3333 [9.3K]
The constraints for the problem is the number of tomatoes and cups of oil on hand. 

There are only 45 tomatoes and 10 cups of oil on hand to make both the Tuscan sauce and Marinara sauce. 

These are identified as constraints because they limit the number of Tuscan sauce and Marinara sauce that Tiffany can make.
4 0
2 years ago
Which algebraic expression represents the phrase "seven more than half of a number"?
Vika [28.1K]

Answer:

1/2x +7

Step-by-step explanation:

Let the unknown number be x

We want 1/2 of the number

1/2x

Then 7 more than  (add)

1/2x +7

4 0
2 years ago
Find the cube roots of 27(cos 330Á + i sin 330Á). Please help c:
Mashcka [7]
Use formula
e^{ix}=\cos{x}+\sin{x}

\sqrt[3]{27(\cos{330^o}+i\sin{330^o})} 
\\\sqrt[3]{27e^{i330^o} }
\\  \sqrt[3]{27}  \sqrt[3]{e^{i330^o}} 
\\ \sqrt[3]{3^3} \sqrt[3]{e^{i110^o\times 3}} 
\\ \sqrt[3]{3^3} \sqrt[3]{(e^{i110^o})^ 3}} 
\\ 3e^{i110^o}
\\3(\cos{110^o}+i\sin{110^o})

Since 330^o=360^o+330^o=690^o
 and 330^o=2\times 360^o+330^o=1050^o there are two more solutions:
1. 3(\cos{230^o}+i\sin{230^o})
2. 3(\cos{350^o}+i\sin{350^o})
4 0
2 years ago
Read 2 more answers
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