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shepuryov [24]
1 year ago
8

Create a storyline (word problem) using the following algebraic expression: 1,000/r

Mathematics
1 answer:
mamaluj [8]1 year ago
7 0

Answer:

Suppose there are 1,000 candies in a jar. There are 50 children in a room. If i want to share 1000 candies among all the children. How can i divide 1,000 candies equally in 50 children.

Step-by-step explanation:

Create a story line(word problem) means to create a fake or real story by translating an algebraic expression in english.

We can create a story by the given 1,000/r:

Suppose there are 1,000 candies in a jar. There are 50 children in a room. If i want to share 1000 candies among all the children. How can i divide 1,000 candies equally in 50 children.

Here r = 50....

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A doctor is measuring the average height of male students at a large college. The doctor measures the heights, in inches, of a s
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Answer:

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

For this case the  95% confidence interval is given (63.5 , 74.4) and we want to conclude about the result. For this case we can say that the true mean of heights for male students would be between 63.5 and 74.4. And the best answer would be:

b. The doctor can be 95% confident that the mean height of male students at the college is between 63.5 inches and 74.4 inches.

3 0
2 years ago
Lily sold 18 items at the street fair. She sold bracelets for $6 each and necklaces for $5 each for a total of $101. Which syste
vladimir2022 [97]

B + N = 18 and 6B + 5N = 101. This is the system of equations you would use.

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On a trip, you had to change your money from dollars to euros. You got 450 euros for 600 dollars.What is a unit rate that descri
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If you divide the amount of Dollars by the amount of Euros you get the price of 1 Euro in Dollars.

$600/450€ = $1,33 per each Euro
4 0
1 year ago
Read 2 more answers
The regular octagon has a perimeter of 122.4 cm. Which statements about the octagon are true? Select two options. The length of
KATRIN_1 [288]

The correct answers on edge are C and E

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2 years ago
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The data set below represents the ages of 36 executives. find the percentile that corresponds to an age of 4141 years old. 2828
solong [7]

Answer:

37th percentile.

Step-by-step explanation:

We have been given a data set that represents the ages of 36 executives. We are asked to find the percentile that corresponds to an age of 41 years.

28, 29, 29, 32, 32, 33, 34, 34, 34, 34, 37, 37, 38, 41, 41, 42, 45, 45, 47, 47, 47, 48, 50, 51, 53, 56, 56, 56, 61, 61, 62, 63, 64, 64, 65, 66.

Let us count the number of data points below and at 41.

We can see that the number of data points at and below 41 is 13.

We will use percentile formula to solve our given problem.

\text{Percentile rank of x}=\frac{\text{Number of values below x}}{\text{Total number of data points}}\times 100

\text{Percentile rank of 41}=\frac{13}{36}\times 100

\text{Percentile rank of 41}=0.361111\times 100

\text{Percentile rank of 41}=36.11\approx 37

Therefore, the percentile rank that corresponds to age of 41 years old is 37th percentile.  

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2 years ago
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