Answer:
See the solutions below
Step-by-step explanation:
Given data
Distance = 24.6km
in meters= 24.6*1000= 24600m
time= 30 minutes
in seconds= 30*60= 1800
int hours= 0.5 hour
speed of the particle in
(i) km/h= 24.6/0.5= 49.2 km/h
(ii) m/s.= 24600/ 1800= 13.66 m/s
Answer:
212m
Step-by-step explanation:
The set up will be equivalent to a right angled triangle where the height is the opposite side facing the 45° angle directly. The length of the rope will be the slant side which is the hypotenuse.
Using the SOH, CAH, TOA trigonometry identity to solve for the length of the rope;
Since we have the angle theta = 45° and opposite = 150m
According to SOH;
Sin theta = opposite/hypotenuse.
Sin45° = 150/hyp
hyp = 150/sin45°
hyp = 150/(1/√2)
hyp = 150×√2
hyp = 150√2 m
hyp = 212.13m
Hence the length of the rope for the kite sail, in order to pull the ship at an angle of 45° and be at a vertical height of 150 m is approximately 212m
Answer:
Step-by-step explanation:
: Read and write decimals to thousandths using base-ten numerals, number names, and expanded form, e.g., 347.392 = 3 × 100 + 4 × 10 + 7 × 1 + 3 × (1/10) + 9 × (1/100) + 2 × (1/1000).
Answer:
F
Step-by-step explanation:
s²+s²=(4√2)²
2s²=32
s²=16
s=4
