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2 years ago

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Noah fills a soap dispenser from a big bottle that contains 2 13 liters of liquid soap. That amount of soap will fill 3 12 dispe

nsers. How many liters of soap fit into one dispenser?

2 answers:

Harrizon [31]2 years ago

3 0

Answer:

0.68L per dispenser

Step-by-step explanation:

Big bottle contain 213L of soap.

Big bottle will fill 312 dispensers.

This means 1 each dispenser can take 213/312 litres = 0.68L per dispenser.

Naya [18.7K]2 years ago

3 0

Answer:

L = 2/3 or 0.67 liters per dispenser

Incorrect question

Corrected question:

Noah fills a soap dispenser from a big bottle that contains 2 1/3 liters of liquid soap. That amount of soap will fill 3 1/2 dispensers. How many liters of soap fit into one dispenser?

Step-by-step explanation:

Total volume of soap in the dispenser = 2 1/3 liters

Converting to improper fraction = 7/3 liters

Total number of dispenser the soap can fill = 3 1/2

Converting to improper fraction = 7/2

How many liters L of soap fit into one dispenser;

L = number of liters per dispenser

L = Volume of soap/number of dispensers

L = 7/3 ÷ 7/2

L = 7/3 × 2/7 = 2/3 liters per dispenser

L = 2/3 or 0.67 liters per dispenser

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-67b + 6 ≤ 9b + 43 solve for b

qaws [65]

Answer:

b ≥ -(37/76)

Step-by-step explanation:

5 0

2 years ago

The amount of soft drink in a bottle is a Normal random variable. Suppose that in 7% of the bottles containing this soft drink t

WITCHER [35]

Answer:

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

7% of the bottles containing this soft drink there are less than 15.5 ounces

This means that when X = 15.5, Z has a pvalue of 0.07. So when X = 15.5, Z = -1.475.

$Z = \frac{X - \mu}{\sigma}$

$-1.475 = \frac{15.5 - \mu}{\sigma}$

$15.5 - \mu = -1.475\sigma$

$\mu = 15.5 + 1.475\sigma$

10% of them there are more than 16.3 ounces.

This means that when X = 16.3, Z has a pvalue of 1-0.1 = 0.9. So when X = 16.3, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{16.3 - \mu}{\sigma}$

$16.3 - \mu = 1.28\sigma$

$\mu = 16.3 – 1.28\sigma$

From above

$\mu = 15.5 + 1.475\sigma$

So

$15.5 + 1.475\sigma = 16.3 – 1.28\sigma$

$2.755\sigma = 0.8$

$\sigma = \frac{0.8}{2.755}$

$\sigma = 0.29$

The mean is

$\mu = 15.5 + 1.475\sigma = 15.5 + 1.475*0.29 = 15.93$

The mean is 15.93 ounces and the standard deviation is 0.29 ounces.

6 0

2 years ago

Erik's disabled sailboat is floating stationary 3 miles east and 2 miles north of Kingston. A ferry leaves Kingston heading towa

sergij07 [2.7K]

Answer:

Step-by-step explanation:

Let's suppose that Ballard is an origin with coordinates (0;0)

Ballard is 8 miles south and 1 mile west of Edmonds ⇒ Edmonds is 1 mile east and 8 miles north of Ballard.

Thus, coordinates of Edmonds (0+1; 0+8) (1;8)

Edmonds is 6 miles due east of Kingston. So, is 6 miles due of Edmonds

Thus, Kingston coordinates (1-6;8) (-5:8)

Sailboat is 3 miles east and 2 miles north of kingston

So, coordinates of sailboat are (-5+3; 8+2) (-2;10)

a)

Ferry leaves Kingston towards Edmonds at mph and Edmonds is 6 miles due east of Kingston.

Initial ferry coordinates as calculated above are equal to Kingston coordinates (-5;8)

After 20 minutes the ferry turns to south.

This distance travelled (20min) is d=9mph*20/60h=3 miles

So, ferry travelled 3 miles toward east in 20 min

Then, coordinates became (-5+3;8+0) (-2;8)

Thus, we have a line connecting two points (-5;8) and (-2;8)

Line connecting them has an equation:

y-8 = (8-8)/(-2+5) * (x+5)

y-8=0

y=8 - This is the equation for the first 20 minutes of travel

Then, ferry turns due south (-2;8) and has a vertiacl line

The equation of verical line is x=a, so the equation will be x=2

b) The sailboat has a radar scope that will detect any object within 3 miles of the sailboat.

region looks like a circular disc with a center (-2;10)

(x+2)^2+(y-10)^2=3^2

(x+2)^2+(y-10)^2 <9 (interior of the circular disc)

(x+2)^2+(y-10)^2 >9 (exterior)

The equation of the line joining the Kingston and Edmonds is y=8

the point of intersection:

(x+2)^2+(8-10)^2=9

(x+2)^2=5

x is approximately 0.24; -4.24

(0.24;8) (-4.24;8) - intersection points

c) The ferry exits the radar during the trid due south long x=-2

The points of intersection of the circle and the line x=-2:

(-2+2)^2+(y-10)^2=9

0+(y-10)^2=0

y is 7.13

(-2;7)

d) Takes south turn at (-2;8), then ferry travels 0.8 miles up to point (-2;7) where it exists the radar zone

Speed is 9mph

The time taken to cover 1 mile = t=1/9hr=1/9 *60=6.667min

So, it exists after 6.67 minutes

e) Ferry enters at (-4.24;8) and takes turn due to south at (-2;8)

The distance travelled is = [-4.24+2]=2.24 miles

The time taken to cover these miles is = t=2.24/9 *60=14.93 min

After turning to south ferry remains in radar for 6.7 min

So, it remains in radar zone for 14.93+6.7=21.63min

8 0

2 years ago

Jessica is 5 years older than her sister Jenna. Jenna tells her sister that in 5 years, she will be as old as Jessica was 5 year

emmasim [6.3K]

      Jenna's age    Jessica's age

today    x    x + 5

in 5 years x+5

5 years ago    x + 5 - 5

Equality x + 5 = x + 5 - 5

=> x + 5 = x

The equation is x + 5 = x

That equation has not any solution, because it reduces to 5 = 0, which is an absurd.

So, the conclusion is that information given by Jenna is wrong.

It is logical: if the difference of the ages is 5, in five years Jenna will have 10 years more than what her sister had 5 years ago, no 5 as she told Jessica.

5 0

2 years ago

Read 2 more answers

The marching band walks 1/15 miles in 1.5 minutes. At this rate, how many minutes will it take to complete 1 mile? Record your a

ipn [44]

Answer:

It will take 22.5 minutes to complete 1 mile

Step-by-step explanation:

From the question,

The marching band walks 1/15 miles in 1.5 minutes

First we will determine the miles cover in 1 minute

If the marching band walks 1/15 miles in 1.5 minutes

then, they will cover $x$ miles in 1 minute

$x = \frac{1/15 * 1}{1.5}\\$

Then,

$x = \frac{1/15 }{1.5}$

$x = 2/45$ miles

∴ 2/45 miles are covered in 1 minute

Now,

If 2/45 miles are covered in 1 minute

Then, 1 mile will be covered in $y$ minute

$y = \frac{1 * 1}{2/45}$

$y =\frac{1}{2/45} \\y = \frac{45}{2}\\$

∴ $y = 22.5 minutes$

Hence, it will take 22.5 minutes to complete 1 mile

6 0

2 years ago