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OverLord2011 [107]
2 years ago
12

Which of the numbers listed below are solutions to the equation? Check all that apply. x2 = 81 A. 18 B. 40.5 C. -9 D. 162 E. 9 F

. 6561
Mathematics
2 answers:
Harman [31]2 years ago
5 0
If 81 equals to x² (so the unknown number is 81 when x is squared), the to find x you do the square root of 81.

x = ±√81

x = <span>±9

Answers are either C and E</span>
Murljashka [212]2 years ago
3 0
X^2 = 81...take the square root of both sides, eliminating the ^2
x = (+-) sqrt 81
x = (+-) 9

answers are : -9 and 9
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The perimeter of a square is represented by the expression 32x - 12.8. Draw a square to represent this situation and label its s
Hoochie [10]

Answer:

Step-by-step explanation:

Given that: The perimeter of a square is: 32x - 12.8

As we all know that, the formula to find the perimeter of a square is:

Sum of the 4 side = 4* length of the side  

=> the length of 1 side: The perimeter of a square  / 4

In this situation, we have length of 1 side side is:

(32x - 12.8) / 4

= 32/4x - 12.8/4

= 8x - 3.2

The 1st equivalent expressions for the perimeter: 4 *(8x - 3.2)

The 2nd equivalent expressions for the perimeter: (8x - 3.2) + (8x - 3.2)  + (8x - 3.2)  + (8x - 3.2)

The 3rd equivalent expressions for the perimeter: 2*(8x - 3.2) + 2*(8x - 3.2)

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1 year ago
On jeopardy there are 5 monetary categories- $100 $200 $300 $400 and $500. Each of them have an equally likely chance of popping
irina [24]

Answer:

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2 years ago
Which of the following expressions are equivalent to −5.93+(−8.62)+5.93?
vampirchik [111]

Answer:

  • A, B, C, D

Step-by-step explanation:

  • −5.93 + (−8.62) + 5.93 =
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  • −(5.93 + 8.62) + 5.93 =       C
  • −5.93 −8.62 - (- 5.93) =       D
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7 0
2 years ago
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Answer: 12.32

Step-by-step explanation:

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7 0
1 year ago
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wel

as far as I can tell, is just a matter of going around the circle many or infinite times around.

so 6,31° is the first point, the next point will be one-go-around, 6, 31+360 => 6, 391°

then the next will be 6, 391+360 => 6, 751° and so on.

so we can say is (6, 31° ±360°n), n ∈ ℤ.

6 0
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