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Ludmilka [50]
2 years ago
6

A delivery truck company just bought a new delivery truck and they need to know the maximum volume it can carry. In the front of

the truck, there is an extra ledge that sticks out over the driver's cab for extra storage space. What is the maximum amount of cargo that can fit into the new truck?

Mathematics
1 answer:
sergejj [24]2 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

To find the maximum amount of cargo the truck can carry, we need to find the volume of the truck.

Volume = length × width × height.

Firstly 1 feet (1') = 12 inches (12"),

For the extra ledge that sticks out, the height = 7'8" = 7.667 feet, the width = 16'9" - 14'3" = 16.75 - 14.25 = 2.5 feet, the length = 2'7" = 2.583 feet

Volume of extra ledge = length × width × height = 2.583 × 2.5 × 7.667 = 49.5 feet³

For the truck, the height = 7'8" = 7.667 feet, the length = 14'3" = 14.25 feet, the width = 6'6" = 6.5 feet

Volume of truck = length × width × height = 14.25 × 6.5 × 7.667 = 710.16 feet³

The maximum volume = volume of extra ledge + volume of truck = 49.5 + 710.16 = 759.66 feet³

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Answer:

Part 1: There are 4.7*10^21 ways to select 40 volunteers in subgroups of 10

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Step-by-step explanation:

Part 1:

The number of ways in which we can organized n elements into k groups with size n1, n2,...nk is calculate as:

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So, in this case we can form 4 subgroups with 10 participants each one, replacing the values of:

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We get:

\frac{ 40!}{10!*10!*10!*10!} = 4.7*10^{21}

Part 2:

The number of ways in which we can choose k element for a group of n elements and the order in which they are chose matters is calculate with permutation as:

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Step-by-step explanation:

Hi!

As you can see in the figure, the point you are looking for is the intersection of two lines.

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