The value of sin(30°) is: One-half ⇒ 2nd answer
Step-by-step explanation:
In a right triangle there are two acute angles, the side opposite to the right angle is called hypotenuse, and the other two sides are opposite and adjacent to the acute angles
- sine the acute angle (sin) = opposite side to it/hypotenuse
- cosine the acute angle (cos) = adjacent side to it/hypotenuse
- Tangent the acute angle (tan) = opposite side to it/adjacent side to it
In Δ QRS:
∵ m∠QRS = 90°
∵ SQ is opposite to ∠QRS
∴ SQ is the hypotenuse
∵ SQ = 10 units
∴ The hypotenuse = 10
∵ m∠RSQ = 30°
- The opposite side to ∠RSQ is RQ
∵ RQ = 5 units
∴ The opposite side to the angle of 30° = 5
∵ sin(30°) = opposite side to 30°/hypotenuse
∵ The opposite side to angle 30° = 5
∵ The hypotenuse = 10
∴ sin(30°) = 
∴ sin(30°) = 
The value of sin(30°) is: One-half
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Answer:
Step-by-step explanation:
Given that two well-known aviation training schools are being compared using random samples of their graduates
Fly more academy 70 of 140
Blue Yonder 104 of 260
Combined pass = (70+104) out of (140+260)
a) Pooled proportion=
b) H0: p1 = p2
Ha: p1 ≠p2
(two tailed test)
p difference= 
std error for difference (using pooled proportion) = 
Test statistic = p difff/std error = 4.034
c) Critical value for 0.05 is 1.96
d) p value is < 0.005
Since p < 0.05 our significant level we reject H0
There is significant difference between the two proportions.
Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78