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scZoUnD [109]
2 years ago
14

8.73e16 in standard form

Mathematics
1 answer:
pentagon [3]2 years ago
7 0
Answer is: 77575744.84403361
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Which of the following is the graph of y = negative 4 StartRoot x EndRoot?
weeeeeb [17]

Answer:

Use a graphing calculator.

Step-by-step explanation:

Graph:

f(x) = -4√x

6 0
2 years ago
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If they charge $2.00 per quart, how much money will they make if they sell it all
Tcecarenko [31]

Answer:

Give me more information


Step-by-step explanation:


5 0
2 years ago
Which statement shows how two polynomials 4x + 6 and 2x2 − 8x demonstrate the closure property when multiplied?
steposvetlana [31]

Answer:

8x^{3} -20x^{2} -48x is a polynomial

Step-by-step explanation:

Given : polynomials 4x+6 and2x^{2} -8x

Solution:

(4x+6)*(2x^{2} -8x)

4x(2x^{2} -8x)+6(2x^{2} -8x)

8x^{3} -32x^{2}+12x^{2} -48x

8x^{3} -20x^{2} -48x

Polynomial :An expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable.

Thus 8x^{3} -20x^{2} -48x is a polynomial

Hence option A is correct.




7 0
2 years ago
Read 2 more answers
HURRY PLEASE The amount of tax for each camera is $5.25 and the tax rate is 6%. Explain how the equation: (Original Cost)(Percen
worty [1.4K]

Answer:

$3.15 is the orignal price

Step-by-step explanation:

4 0
1 year ago
Sales personnel for Skillings Distributors submit weekly reports listing the customer contacts made during the week. A sample of
Thepotemich [5.8K]
<h2><u>Answer with explanation</u>:</h2>

As per given , we have

sample size : n= 65

degree of freedom : df=n-1=64

sample mean : \overline{x}=19.5

sample standard deviation : s= 5.2

Since , the population standard deviation is not given  , so we apply t-test.

Significance level  for 90% confidence : \alpha=1-0.90=0.10

t-critical value for significance level 0.10 and df = 64 would be :

t_c=t_{\alpha/2, df}=t_{0.05,\ 64}=1.6690

Formula for Confidence interval :

\overline{x}\pm t_c\dfrac{s}{\sqrt{n}}

Then , 90%  confidence intervals for the population mean number of weekly customer contacts for the sales personnel would be :

19.5\pm(1.669)\dfrac{5.2}{\sqrt{65}}

=19.5\pm1.076

(19.5-1.076,\ 19.5+1.076)=(18.424,\ 20.576)

∴ 90% confidence intervals for the population mean number of weekly customer contacts for the sales personnel : (18.424, 20.576)

Significance level  for 95% confidence : \alpha=1-0.95=0.05

t-critical value for significance level 0.05 and df = 64 would be :

t_c=t_{\alpha/2, df}=t_{0.05,\ 64}=1.9977

Then , 95%  confidence intervals for the population mean number of weekly customer contacts for the sales personnel would be :

19.5\pm(1.9977)\dfrac{5.2}{\sqrt{65}}

=19.5\pm1.288

(19.5-1.288,\ 19.5+1.288)=(18.212,\ 20.788)

∴ 95% confidence intervals for the population mean number of weekly customer contacts for the sales personnel : (18.212, 20.788)

4 0
2 years ago
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