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kolbaska11 [484]
2 years ago
5

A function f(x) has x intercepts of -3 and -5. What is the constant term in the function?

Mathematics
1 answer:
Anon25 [30]2 years ago
3 0

Answer:

The constant term in the function is 5

Step-by-step explanation:

we have

f(x)=x^{2}+8x+b

where

b is the y-intercept or the constant term of the function

Remember that

The x-intercept is the value of x when the value of the function is equal to zero

so

For x=-3 ----> f(x)=0

For x=-5 ----> f(x)=0

substitute any of the intercepts in the function

For x=-3

0=(-3)^{2}+8(-3)+b

0=9-24+b

0=-15+b

b=15

f(x)=x^{2}+8x+15

Verify with the other intercept

For x=-5

0=(-5)^{2}+8(-5)+15

0=25-40+15

0=0 ---> is true

therefore

The constant term in the function is 5

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