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2 years ago

A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH is followed by .

Mathematics

2 answers:

choli [55]2 years ago

5 0

Answer:

<h2>A rotation -90° around point I.</h2><h2>A translation upwards 2 units.</h2><h2>Step-by-step explanation:</h2>

The given figures are attached.

We have to find two transformations that help to show that both polygon are congruent.

First transformation would be a rotation -90° around point I.

Second transformation would be a translation upwards 2 units.

Applying these transformation, we would have both polygons at the same position, that will show the congruence between them.

alexgriva [62]2 years ago

4 0

Answer: A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH is a reflection across the x-axis followed by a 90° clockwise rotation about point D

Step-by-step explanation:

If you reflect polygon ABCDE over the x-axis point D will fall over point I from Polygon GFJIH, then by doing a 90° clockwise rotation, the image is congruent, i'll atach an image for you to see the process.

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Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim

Xelga [282]

Answer: P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = $\frac{2.\pi}{B}$

C is the phase shift or horizontal shift: $\frac{C}{B}$

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

<u>Amplitude</u>:

a = $\frac{largest - smallest}{2}$

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = $\frac{6.9-4.4}{2}$

a = 1.25

A time period for Pluto is T=66 years:

66 = $\frac{2.\pi}{b}$

b = $\frac{\pi}{33}$

<u>Vertical</u> <u>Shift</u>

It can be calculated as:

d = $\frac{largest+smallest}{2}$

d = $\frac{6.9+4.4}{2}$

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

8 0

2 years ago

Find the cube root of 8x7x9x49x3

vodka [1.7K]

Answer:

=42

Step-by-step explanation:

The expression 8×7×9×49×3 can be written in its simplest factor form as follows.

8=2³

49=7²

9=3²

Thus the expression becomes:2³×7×3²×7²×3

Combine the indices to the same base.

2³×3³×7³

Finding the cube root involves dividing the index by three.

Thus ∛(2³×3³×7³)= 2×3×7

=42

5 0

2 years ago

Set of negative integers greater than -6. Write the given sets in roster form.

LiRa [457]

I don't know what rosters form is but the integers are -5, -4, -3, -2, and -1.

7 0

2 years ago

Pedro has created the function f(x)= 4x-3/2 to represent the number of assingments he has completed where x represents the numbe

Law Incorporation [45]

The given function is
f(x) = 4x - 3/2
where
f(x) = number of assignments completed
x = number of weeks required to complete the assignments

We want to find f⁻¹ (30) as an estimate of the number of weeks required to complete 30 assignments.
The procedure is as follows:

1. Set y = f(x)
y = 4x - 3/2

2. Exchange x and y
x = 4y - 3/2

3. Solve for y
4y = x + 3/2
y = (x +3/2)/4

4. Set y equal to f⁻¹ (x)
f⁻¹ (x) = (x + 3/2)/4

5. Find f⁻¹ (30)
f⁻¹ (30) = (30 + 3/2)/4 = 63/8 = 8 (approxmately)

Answer:
Pedro needs about 8 weeks to complete 30 assignments.

6 0

2 years ago

Nine new employees, two of whom are married to each other, are to be assigned nine desks that are lined up in a row. If the assi

meriva

Answer:

The probability is 0.8

Step-by-step explanation:

The key to answering this question is considering the fact that the two married employees be treated as a single unit.

Now what this means is that we would be having 8 desks to assign.

Mathematically, the number of ways to assign 8 desks to 8 employees is equal to 8!

Now, the number of ways the couple can interchange their desks is just 2 ways

Thus, the number of ways to assign desks such that the couple has adjacent desks is 2(8!)

The number of ways to assign desks among all six employees randomly is 9!

Thus, the probability that the couple will have adjacent desks would be ;

2(8!)/9! = 2/9

This means that the probability that the couple have non adjacent desks is 1-2/9 = 7/9 = 0.77778

Which is 0.8 to the nearest tenth of a percent

4 0

2 years ago