The cost of the tuitions will if you round off 43:000 it would $43
Answer:
The conclusion that both groups of overweight and non - overweight got cardiovascular benefit from playing DDR games requires Inferential statistics.
Step-by-step explanation:
Inferential statistics is simply a type of research statistic whereby a generalized conclusion is made about a larger group based on representative observations
Now,in the given question, we see that both group hearts were above the minimum recommended for cardiovascular exercise. Now we can infer that the DDR games played by both groups gave them cardiovascular benefits. This conclusion is an example of Inferential statistics where we generalize about a large population based on observations from a small sample.
Thus the conclusion that both groups of overweight and non-overweight got cardiovascular benefit from playing DDR games requires Inferential statistics.
Correct question:
Which reaction describes a beta emission? 2659Fe→ 2759Co + −10e, 88226Ra→ 86222Rn + 24He, 94239Pu + 24He→ 96242Cm + 01n, 54118Xe→ 53118I + +10e
Answer:
2659Fe→ 2759Co + 1e
Step-by-step explanation:
General equation for beta decay is given as;

where;
A is the atomic mass of the element
z is atomic number of the element
X is the parent atom
Y is the daughter element
β is beta emission
In beta emission, there is loss of one electron and zero proton, the will cause the daughter element to gain on electron in order to balance the reaction.
Based on beta decay equation above, we select the reaction that describes beta emission.
2659Fe→ 2759Co + 1e
Here;
A = 59
z = 26
z + 1 = 27
Answer:
0.0406, 0.8284,0.7887
Step-by-step explanation:
Given that Mattel Corporation produces a remote-controlled car that requires three AA batteries
X is N(34, 5.5)
Hence sample size of 25 would follow a t distribution with df = 24
This is because sample size <30
t distribution with df 24 would be bell shaped symmetrical about the mean and unimodal.
Std error of sample mean = std dev /sqrt n=
Prob (X>36) = 
i.e nearly 4.1% of the sample would have a mean useful life of more than 36 hours
X>33.5 implies 
=0.82837
=0.8284 proportion will have a mean useful life greater than 33.5 hours
Proportion between 33.5 and 36 hours
= 