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solong [7]
2 years ago
15

Roberto's toy car travels at 30 centimeters per second (cm/sec) at high speed and 20 cm/sec at low speed. If the car travels for

20 seconds at high speed and then 30 seconds at low speed, what distance would the car have traveled
Mathematics
2 answers:
amm18122 years ago
7 0

Answer:

15 seconds at high speed

1 sec = 40 cm

15 sec = 40 x 15

15 sec = 600 cm

30 seconds at low speed

1 sec = 15 cm

30 sec = 15 x 30  

30 sec = 450 cm

Total distance = 600 + 450 = 1050 cm

Step-by-step explanation:

igomit [66]2 years ago
3 0

Answer:

1200 cm

Step-by-step explanation:

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pickupchik [31]
My answer is: D. <span>(6,0,0)

Given: 
</span><span> 7x +2y +3z =42

I assumed that the format in the given choices is (x,y,z). So, I substituted each number to its corresponding variable.

A. </span>(14,0,0)  → 7(14) +2(0) +3(0) = 42 → 98 + 0 + 0 ≠ 42  NOT THE ANSWER<span>
B. (7,0,0) </span>→ 7(7) +2(0) +3(0) = 42 → 49 + 0 + 0 ≠ 42 NOT THE ANSWER<span>
C. (21,0,0) </span>→ 7(21) +2(0) +3(0) = 42 → 147 + 0 + 0 ≠ 42 NOT THE ANSWER<span>
D. (6,0,0) </span>→ 7(6) +2(0) +3(0) = 42 → 42 + 0 + 0 = 42 CORRECT ANSWER.


<span>The ordered triples indicated where the plane cuts the x-axis for this equation is D. (6,0,0). </span>
4 0
2 years ago
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A given line has the equation 10x+2y=-2.
Karolina [17]

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Step-by-step explanation:

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Answer:

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