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1 year ago

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Simon has a quarter, dime, nickel, and penny in his pocket. He wants to buy a snack at the canteen that costs 40¢. If he pulls o

ut one coin at a time, what is the probability that the first 3 coins that are equal to $0.40?
The completed formula is ___c____3=____
There are___items. He will choose____

1 answer:

ludmilkaskok [199]1 year ago

8 0

Answer:

It would be a 3/4 chance that he will pull the right 4 coins.

Step-by-step explanation:

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The expression sinx + cotx cosx can be simplified to___. A. cotx B. cscx C. cosx sinx D. secx

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$\sin x+\cot x\cos x=\sin x+\dfrac{\cos x}{\sin x}\cos x=\dfrac1{\sin x}(\sin^2x+\cos^2x)=\csc x$

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THIS IS URGENT I NEED THIS AS SOON AS POSSIBLE! YOUR HELP WOULD BE GREATLY APPRECIATED!

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Answer:

Strawberries sold 44 baskets

Raspberries sold 52 baskets

Step-by-step explanation:

$4x + 9y = 644 \\ x + y = 96 \\ 4x + 4y = 384 \\ 5y = 260 \\ y = 52 \\ x = 44$

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Jeremiah and Tristan work at a dry cleaners ironing shirts. Jeremiah can iron 35 shirts per hour, and Tristan can iron 20 shirts

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The number of hours Jeremiah ironed = 10 hours

The number of hours Tristan ironed = 7 hours

<u>Step-by-step explanation</u>:

Jeremiah can iron = 35 shirts per hour
Tristan can iron = 20 shirts per hour
Total work done by both = 490 shirts

Let 'x' be the number of hours Jeremiah ironed.

Let 'y' be the number of hours Tristan ironed.

x+y = 17 ------(1)

35x + 20y = 490 -------(2)

Multiply (1) by 20 and subtract (2) from (1),

20x + 20y = 340

-(<u>35x + 20y = 490</u>)

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x = 150/15

x = 10

Substitute x=10 in (1)

10+y = 17

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1 year ago

Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th

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Answer:

$sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}$

Step-by-step explanation:

Start by noticing that the angle $\theta$ is on the 4th quadrant (between $\frac{3\pi}{2}$ and $2\pi$ . Recall then that in this quadrant the functions tangent and cosine are positive, while the function sine is negative in value. This is important to remember given the fact that tangent of an angle is defined as the quotient of the sine function at that angle divided by the cosine of the same angle:

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Now, let's use the information that the tangent of the angle in question equals "-1", and understand what that angle could be:

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-1=\frac{sin(\theta)}{cos(\theta)}\\-cos(\theta)=sin(\theta)$

The particular special angle that satisfies this (the magnitude of sine and cosine the same) in the 4th quadrant, is the angle $\frac{7\pi}{4}$

which renders for the cosine function the value $\frac{\sqrt{2} }{2}$ .

Now, since we are asked to find the value of the secant of this angle, we need to remember the expression for the secant function in terms of other trig functions: $sec(\theta)=\frac{1}{cos(\theta)}$

Therefore the value of the secant of this angle would be the reciprocal of the cosine of the angle, that is: $sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}$

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Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

lys-0071 [83]

<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>

<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

$2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$

Lets divide the expression by $2x^2\:-\:3x\:+\:1$

Solution Steps:

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}$

Factorizing

$2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}$

Factorizing

$2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)$

$\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}$

$\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2$

$x^2+5x-2$

Thus,

$\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2$

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as $x^2+5x-2$ after dividing $2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2$ by $2x^2\:-\:3x\:+\:1$ , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

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1 year ago

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