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alina1380 [7]
2 years ago
5

What is the following product? (StartRoot 12 EndRoot + StartRoot 6 EndRoot) (StartRoot 6 EndRoot minus StartRoot 10 EndRoot)

Mathematics
2 answers:
worty [1.4K]2 years ago
8 0

Answer:

x = 4 ± \sqrt{19}

Step-by-step explanation:

Crank2 years ago
5 0

Answer:

The product results in: 6\,\sqrt{2} -2\,\sqrt{30} +6-2\,\sqrt{15}, which agrees with answer A of the given choices.

Step-by-step explanation:

We need to apply distributive property for the product of two expressions each consisting of two terms, and also use the properties of products of radicals of the same root:

(\sqrt{12} +\sqrt{6} )(\sqrt{6} -\sqrt{10} )=\\=\sqrt{12*6} -\sqrt{12*10} +\sqrt{6*6} -\sqrt{6*10} =\\=\sqrt{72} -\sqrt{120} +\sqrt{36} -\sqrt{60}

and now, we extract as many factors we can from the roots to reduce them:

\sqrt{72} -\sqrt{120} +\sqrt{36} -\sqrt{60} =\\=6\,\sqrt{2} -2\,\sqrt{30} +6-2\,\sqrt{15}

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