Emily folded a paper circle into 2 equal parts. What is the angle measure of each part?

A process that produces bottles of shampoo, when operating correctly, produces bottles whose contents weight, on average, 20 oun

valentinak56 [21]

Answer:

a. Descriptive statistics for the sample.

n= 9

mean X[bar]= 20.36

median Me= 20.30

min: 19.70

max: 21.40

standad deviation S= 0.61

b. 95% Confidence interval [19.88; 20.83]

c. Decision: Support H₀

Step-by-step explanation:

Hello!

I don't have excel so I cannot install PHstat, I've used a statistic software called Infostat for the calculations.

There was a random sample of 9 bottles of shampoo taken to test if the process is operating correctly. If it is, the bottles should weight on average 20 ounces (this would be our study parameter)

The study variable is X: the weight of a bottle of shampoo.

X~N(μ;σ²)

a.

Descriptive statistics for the sample.

n= 9

mean X[bar]= 20.36

median Me= 20.30

min: 19.70

max: 21.40

standad deviation S= 0.61

b. 95% Confidence interval.

Since the variable has a normal distribution and the population variance is unknown, the statistic to use to construct this interval is the Students t:

X[bar] ± $t_{n-1; 1- \alpha /2}$ * (S/√n)

20.36 ± $t_{8; 0.975}$ * (0.61/√9)

[19.88; 20.83]

c. You have to test the hypothesis that the production is operating correctly, if it is so, then:

H₀: μ = 20

H₁: μ ≠ 20

α: 0.05

The statistic value is t $_{H0}$ = 1.74

p-value: 0.1198

When you use the p-value to decide on a statistical hypothesis, you should always contrast it with the level of significance using the following rule:

If p-value ≤ α, then you reject the null hypothesis.

If p-value > α, then you do not reject the null hypothesis.

Since the p-value is greater than the significance level, you do not reject the null hypothesis. This means that the average weight of the shampoo bottles is 20 ounces, i.e. the process is operating correctly.

I hope it helps!

5 0

1 year ago

I need help with finding the equation for #20 and # 22 for my brother we get the answer but it’s hard for us to write out how to

Pavel [41]

Answer:

Im not sure about 20 but 22 is 48

Step-by-step explanation:

4×96 =384

384÷8 = 48 orange per classroom

8 0

2 years ago

There are two jobs you can apply for. the first job pays $22,000 the first year, with raises of $4,000 each year thereafter. the

jasenka [17]

We let the number of years that the two jobs will have the same payment be denoted as t. Equating the wages of these two jobs after t - 1 years will give us an equation of,
22,000 + 4000(t -1) = 26,000 + 2000(t - 1)
The value of t from the generated equation is 3. Therefore, after 3 years the jobs will be paying the same wages.

7 0

2 years ago

Read 2 more answers

Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4

vekshin1

Given:

The given equation is $\log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)$

We need to determine the extraneous solution of the equation.

Solving the equation:

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule $\log _{c}(a)+\log _{c}(b)=\log _{c}(a b)$ , we get;

$\log _{4}(x(x-3))=\log _{4}(-7 x+21)$

Again applying the log rule, if $\log _{b}(f(x))=\log _{b}(g(x))$ then $f(x)=g(x)$

Thus, we have;

$x(x-3)=-7 x+21$

Simplifying the equation, we get;

$x^2-3x=-7 x+21$

$x^2+4x=21$

$x^2+4x-21=0$

Factoring the equation, we get;

$(x-3)(x+7)=0$

Thus, the solutions are $x=3, x=-7$

Extraneous solutions:

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

$\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)$

$\log _{4}(3)+\log _{4}(0)=\log _{4}(0)$

Since, we know that $\log _{a}(0)$ is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

$\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)$

$\log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)$

Simplifying, we get;

Undefined = $\log _{4}(70)$

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

7 0

1 year ago

Read 2 more answers

Compute the integral (a) int sin (pi x) dx by letting u = pi x. (b) int e^(x/2) dx by letting u = x/2. Show that you got the cor

Maslowich

Answer:

(a) $\int sin(\pi x) dx$ $=-\frac {cos \pi x}{\pi}+c$

(b) $\int e^\frac{x}{2} dx$ $=2e^\frac{x}{2}+c$

Step-by-step explanation:

(a)

$\int sin(\pi x) dx$

Let u = π x

differentiating with respect to x

du = π dx

$\Rightarrow dx=\frac{du}{\pi}$

Putting the value of x and dx

$=\int sin u \frac{du}{\pi}$

$=\frac{-cos u}{\pi}+c$ [ c is an arbitrary constant]

Now putting the value of u

$=-\frac {cos \pi x}{\pi}+c$

(b)

$\int e^\frac{x}{2} dx$

Let $u=\frac{x}{2}$

differentiating with respect to x

$du= \frac{1}{2} dx$

2du = dx

Putting the value of x and dx

= $\int e^u.2.du$

= $2e^u +c$

Now putting the value of u

$=2e^\frac{x}{2}+c$ [ c is an arbitrary constant]

3 0

2 years ago

Emily folded a paper circle into 2 equal parts. What is the angle measure of each part?​

Emily folded a paper circle into 2 equal parts. What is the angle measure of each part?