Answer:
Step-by-step explanation:
The formula for determining the area of a rectangle is expressed as
Area = length × width
Length = 100 m
Width = 52 m
Area of rectangle = 100 × 52 = 5200 m²
A semicircle is half of a circle
The formula for determining the area of a semicircle is
Area = 1/2 × πr²
Diameter = 52 m
Radius = diameter/2 = 52/2
Radius = 26 m
The area of each semicircle is
1/2 × 3.14 × 26² = 1061.32 m²
The area of the surface of the pool is
1061.32 + 1061.32 + 5200 = 7322.64 m²
Answer:
mean (μ) = 4.25
Step-by-step explanation:
Let p = probability of a defective computer components = 
let q = probability of a non-defective computer components = 
Given random sample n = 25
we will find mean value in binomial distribution
The mean of binomial distribution = np
here 'n' is sample size and 'p' is defective components
mean (μ) = 25 X 0.17 = 4.25
<u>Conclusion</u>:-
mean (μ) = 4.25
Answer:
2/3 ÷ 4=1/6
Step-by-step explanation:
2/3÷4=2/3×1/4
=1/3×2
=1/6
Let s represent number of shirts and h represent number of hats.
We have been given that the organizers of a talent show have budgeted $1800 to buy souvenir clothing to sell at the event. They can buy shirts for $10 each and hats for $8 each.
The cost of s shirts would be
and cost of h hats would be
. The cost of s shirts and h hats should be less than or equal to 1800. We can represent this information in an inequality as:

We are also told that organizers plan to buy at least 5 times as many shirts as hats. This means that number of shirts should be greater than or equal to 5 times hats. We can represent this information in an inequality as:

Therefore, the second inequality should be
and option C is the correct choice.
Answer:
the estimation of the size of the population after 20 hours is 10159
Step-by-step explanation:
The computation of the size of the population after 20, hours is shown below;
= 100 2^(20 by 3)
= 10159.36
If we divide 20 by 3 so it would give 6.66 that lies between 6 and 7
So the estimation of the size of the population after 20 hours is 10159
hence, the same is relevant