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RideAnS [48]
1 year ago
14

Linda Gramham's Cinnamon Sugar Graham Cupcake recipe for 36 cupcakes requires 1 1/4 cups of sugar. How much sugar is required fo

r 900 cupcakes? Reduce to lowest terms.
Mathematics
1 answer:
Anon25 [30]1 year ago
5 0

Answer:

31.25 or 31  1/4 cups

Step-by-step explanation:

1  1/4 = 36

x = 900

=> 5/4 = 36

    x = 900

Cross multiply

=> 5/4 * 900 = 36 * x

=> 4500/4 = 36x

=> 1125 = 36x

=> 1125 / 36 = 36x / 36

=> 31.25 = x

31.25 = 31  1/4

So, 31.25 or 31 1/4 cups are required for 900 cupcakes.

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What does it mean in context of the example that Alyssa’s rate of change is greater than Sarah’s?
faltersainse [42]

Answer:

Part 1) The rate of change is the amount of money saved by week

Part 2) The amount of money saved weekly by Alyssa is greater than the amount of money saved weekly by Sarah.

Part 3) see the explanation

Step-by-step explanation:

see the attached figure to better understand the problem

<u><em>The complete question is</em></u>

Part 1) What does the rate of change in the example represent?

Part 2)  What does it mean in context of the example that Alyssa’s rate of change is greater than Sarah’s?

Part 3) Write ordered pairs for the initial values of each function. Tell what the initial values represent

Part 1) we know that

The rate of change is the slope or unit rate of the linear equation

The formula of slope is "rise over run", where the "rise" (means change in y, up or down) and the "run" (means change in x, left or right)

In this context the rate of change is the amount of money saved by week

Part 2) we know that

Alyssa’s rate of change is equal to $8 per week

Sarah’s rate of change is equal to $6 per week

That means ----> The amount of money saved weekly by Alyssa is greater than the amount of money saved weekly by Sarah.

Part 3) we know that

The initial value or y-intercept is the value of y when the value of x is equal to zero

In this context , the initial value is the amount of money available at the time of beginning to save

so

<em>Sarah's Savings</em>

Looking at the graph

The initial value is the point (0,8)

That means ----> At the beginning (x=0), Sarah already had $8 saved.

<em>Alyssa's Savings</em>

Looking at the graph

The initial value is the point (0,0)

That means ----> At the begin (x=0), Alyssa had nothing saved.

8 0
2 years ago
Kona wants to bake at most 30 loaves of banana bread and nut bread for a bake sale. Each loaf of banana bread sells for $2.50,an
Mila [183]

Answer:

Step-by-step explanation:

30 loaves of banana bread and nut bread at most

Banana bread is sold for $2.5

Nut bread is sold for $2.75

Total income she wants to make $44

Given that x represent loaves of bread

And y represent loaves of nut bread

First statement

She wants to make at most 30 of both loaves bread and nut, at most means the maximum she wanted to make is 30, so it is either 30 or less than 30.

Therefore the sum of the loaves bread and the nut bread is less or equal to 30.

Mathematically,

x+y≤30. Equation 1

Second statement

She wants to make at least a gain of $44, that is, the minimum money she wants to make is $44

Banana bread is sold for $2.5

Therefore she will make 2.5x by banking x nut bread

Nut bread is sold for $2.75

She will make 2.75y by baking y nut bread.

Therefore,

Since she wants to make at least $44,

The inequality is,

2.5x+2.75y≥ 44. equation 2

The inequalities model are

1. x+y≤30

2. 2.5x+2.75y≥ 44

3 0
1 year ago
Graph on a coordinate plane each set of (x, y) values. Which set of values describes two quantities that are in a proportional r
Ray Of Light [21]

Answer:

(3, 5.1)(0, 0)(5, 8.5)

Step-by-step explanation:

A proportional relationship occurs only with a linear relationship that goes through the origin.

8 0
2 years ago
Let f(x)=4x-1 and g(x)=2x^2+3. Perform each function operations and then find the domain.
Triss [41]
F(x) = 4x - 1
g(x) = 2x² + 3

1. (f + g)(x) = (4x - 1) + (2x² + 3)
    (f + g)(x) = 2x² + 4x + (-1 + 3)
    (f + g)(x) = 2x² + 4x + 2
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

2. (f - g)(x) = (4x + 1) - (2x² + 3)
    (f - g)(x) = 4x + 1 - 2x² - 3
    (f - g)(x) = -2x² + 4x + 1 - 3
    (f - g)(x) = -2x² + 4x - 2
    Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
    (g - f)(x) = 2x² + 3 - 4x + 1
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    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

4. (f · g)(x) = (4x + 1)(2x² + 3)
    (f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
    (f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
    (f · g)(x) = 8x³ + 12x + 2x² + 3
    (f · g)(x) = 8x³ + 2x² + 12x + 3
    Domain: {x| -∞ < x < ∞}, (-∞, ∞)

5. (\frac{f}{g})(x) = \frac{4x - 1}{2x^{2} + 3}
    Domain: 2x² + 3 ≠ 0
                         - 3  - 3
                        2x² ≠ 0
                         2      2
                          x² ≠ 0
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6. (\frac{g}{f})(x) = \frac{2x^{2} + 3}{4x - 1}
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                         x ≠ 0
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6 0
2 years ago
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