Answer:
11.58%
Step-by-step explanation:
The initial volume if blood flowing through the artery is given by

To achieve a new volume of 155% (55% increase) of the initial volume, the new radius must be:
![V'= 1.55V\\1.55V=k(r')^4\\1.55kr^4 = k(r')^4\\(\sqrt[4]{1.55}*r)^4=(r')^4 \\(1.1158*r)^4=(r')^4 \\r'=1.1158*r](https://tex.z-dn.net/?f=V%27%3D%201.55V%5C%5C1.55V%3Dk%28r%27%29%5E4%5C%5C1.55kr%5E4%20%3D%20k%28r%27%29%5E4%5C%5C%28%5Csqrt%5B4%5D%7B1.55%7D%2Ar%29%5E4%3D%28r%27%29%5E4%20%5C%5C%281.1158%2Ar%29%5E4%3D%28r%27%29%5E4%20%5C%5Cr%27%3D1.1158%2Ar)
Since the new radius is 1.1158 times larger than the initial radius, the percentage increased is:

Answer:
Check the explanation
Step-by-step explanation:
One way ANOVA
The null and alternative hypothesis for this one way ANOVA is given as below:
Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.
Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.
The ANOVA table with calculations can be seen in the attached images below:
In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.
In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.
To solve this question, I did an equation:
0.75x + 1.20y = 120
0.75(95) + 1.20(35) = 120
Then multiply:
71.25 + 42 = 120
Now to check:
71.25 + 42 = 113.25
Answer: 120 - 113.25 = $6.75 Hope this helps
Using a graphing tool
Let's graph each of the cases to determine the solution of the problem
<u>case A)</u>
see the attached figure N 
The range is the interval--------> (0,∞)

therefore
the function
is not the solution
<u>case B)</u> 
see the attached figure N
The range is the interval--------> (0,∞)

therefore
the function
is not the solution
<u>case C)</u>
see the attached figure N
The range is the interval--------> (-∞,3)

therefore
the function
is the solution
<u>case D)</u>
see the attached figure N
The range is the interval--------> (-3,∞)

therefore
the function
is not the solution
<u>the answer is</u>
Answer: 0.46, 0.056, the distribution is approximately normal
Step-by-step explanation: The shape is approximately normal since the expected number of successes equals 36.8 and the expected number of failures equals 43.2 are both larger than 10